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3 years ago

HELP! WILL GIVE BRAINLIEST!

Mathematics

2 answers:

goblinko [34]3 years ago

6 0

Answer:

(2x+16) + (x) = 180

Step-by-step explanation:

The opposite angles of a quadrilateral inscribed inside a circle will be supplementary angles, meaning that A+C=180, and B+D=180. A+C is not given in the answers below, but B+D is, so that is the correct answer.

Hope this helps! Please give brainliest!!

Salsk061 [2.6K]3 years ago

4 0

Answer:

Step-by-step explanation:

Opposite angles of a quadrilateral are supplementary

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The sun appears to move across the sky, because the earth spins on its axis. To a person standing on the earth, the sun subtends

Liono4ka [1.6K]

Answer:

128 seconds

Step-by-step explanation:

The sun subtends an angle $\theta=9.28\times10^{-3}$ rad

Angular velocity equation is $\omega = \frac{\theta}{t}$

where $\omega$ is angular velocity and t is time.

Earth spins at a rate of :

$\omega = \frac{2 \pi rad}{24 h \times \frac{3600 s}{1 h}} = 7.27221\times10^{-5}$ rad/s

Isolating time (t) from angular velocity equation gives:

$\omega = \frac{\theta}{t}$

$t = \frac{\theta}{\omega}$

$t = \frac{9.28\times10^{-3}}{7.27221\times10^{-5}}$

$t = 128 s$

8 0

3 years ago

The slope of the line below is -1. write the point-slope equation of the line using the coordinates of the labeled point.

omeli [17]

Answer:

y+9=-1(x-4)

Step-by-step explanation:

Point Slope Form is:

$y-y_1=m(x-x_1)$

When:

'm' is the slope.

$(x_1,y_1)$ is the coordinate.

We are given the slope of -1 and the coordinate of (4,-9).

So:

$m=-1\\x_1=4\\y_1=-9$

Using the information and replacing the values we get:

$y+9=-1(x-4)$

So, the line equation in point slope form should be: y+9=-1(x-4)

<em>Brainilest Appreciated. </em>

5 0

3 years ago

Read 2 more answers

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

5 0

3 years ago

In the graphic below, ARV = ENV by:

GREYUIT [131]

The ans should be ASA because angle AVR is equal to angle EVN (opposite angles equal)

8 0

3 years ago

Help with practice problem

padilas [110]

Answer:

attached above with detail explanation.