<span>The easiest thing to do is convert all the measurements to yards...
18ft = 6 yards
6 inch = 1/6 yard ( 6 inches = 1/2 ft.... so 1/6 yard)
so the volume is
V = 6 x 6 x 1/6
Then all you do is calculate the cost. I hope this helps you out</span>
Answer:
The discount is the same.
Step-by-step explanation:
We need to find the ratios of both discounts.
41/50 = 61.5/75
If the question is True, this means that the ratios should be the same. So we have to cross multiply to find the answer.
75*41 = 50*61.5 = 3075
These two multiplication problems both equal 3075. Since the ratios are equal, the discounts are also equal.
Answer:

Step-by-step explanation:
A polynomial is given to us and we need to make the polynomial by its degree . Here the given polynomial is 3x² + 5x -3 .

So here we can see that the highest power of the variable in the given polynomial is 2 . So the polynomial is a quadratic polynomial .
<u>★</u><u> </u><u>More </u><u>to </u><u>Know </u><u>:</u><u>-</u>
When we equate this quadratic polynomial with 0 , it becomes a quadratic equation.
That is ,
This is done in order to find the zeroes of the polynomial. The zeroes of the polynomial are the values for which the polynomial becomes 0 .
Answer:
35
Step-by-step explanation:
We know the factors of Lena's age are 2 and 5. The least common multiple must have these factors and the factors of 14, so will at least have factors of 2, 5, and 7.
Apparently, the dad's age is 5·7 = 35.
___
The GCF is 5; the LCM is 70 = 5×14.
_____
Sometimes, I use a little 3-part diagram to think about LCM and GCF. Here, it would look like ...
(2 [5) 7]
where the numbers in curved brackets (2·5) and the numbers in square brackets [5·7] are factors of the two numbers of concern (Lena's age, her dad's age). The middle number in both brackets [5) is the greatest common factor, and the product of all three numbers is their least common multiple.
Here, the product of outside numbers, 2·7 = 14, represents the ratio of the LCM to the GCF. We know that Lena's age has factors of only 2 and 5, so the numbers in the diagram have to be (2[5)7], where 2 and 7 are on the ends and 5 is in the middle.