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Sauron [17]
4 years ago
7

Determine the largest interval of the form a

Mathematics
1 answer:
vovikov84 [41]4 years ago
3 0
I am currently on break but I think the answer may be <span>< t < b, hopefully I am correct.

If there is anything else you would like me to assist in, I am here but mathematics are not one of my strong points. <sigh></span>
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I NEEP HELP ASAP PLEASE AND THANK YOU
sertanlavr [38]

Answer:

The first answer, 3 times the square root of x squared is correct.

8 0
3 years ago
Does anyone know the answer???
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

R=50+20t, B=150-20t they will be the same height when

50+20t=150-20t

50+40t=150

40t=100

t=2.5, usingvthis value for t in either original equation will give you the height.

h=50+20(2.5)

h=100m

7 0
3 years ago
Read 2 more answers
Which table of ordered pairs matches the following function?<br><br> y=-1/2x - 1
abruzzese [7]

Answer:

second one

Step-by-step explanation:

3 0
3 years ago
4(4x-2) + 1 =16x - 7. Solutions
Talja [164]

Answer:

4(4x - 2) + 1 = 16x - 7

16x - 8 + 1 = 16x - 7

16x - 7 = 16x - 7

-7 = -7

0 = 0

6 0
3 years ago
A converging lens of focal length 5 cm is placed at a distance of 20
lesya [120]

The object should be placed 20/cm from the lens so as to form its real image on the screen

<h3>Mirror equation</h3>

The mirror equation is given according to the expression below;

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

Given the following parameters

f = 5cm

v = 20cm

Required

object distance u

Substitute

1/5 = 1/u +1/20

1/u = 1/5-1/20
1/u = 3/20

u = 20/3 cm

Hence the object should be placed 20/cm from the lens so as to form its real image on the screen

Learn more on mirror equation here; brainly.com/question/27924393

#SPJ1

4 0
2 years ago
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