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Tasya [4]
4 years ago
8

What is the midpoint between (-5,4) and (-6,7)

Mathematics
1 answer:
just olya [345]4 years ago
8 0
(-5.5,5.5)
You need to average -5 and -6
And 7 and 4
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Math question in the attached text
arsen [322]

Answer:

A 1.44 cm cubed

Step-by-step explanation:

Just multiply all the numbers to get the area of the block

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3 years ago
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HELP!!!! 3. Find the x-intercept of the graph of the linear equation y = 2x + 4.
Naily [24]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

(-2, 0)

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\text{Substitute in \textbf{0} for } y \text{ and solve for } x\text{.}\\-------------------\\y = 2x+4\\-------------------\\\rightarrow 0 = 2x +4\\\\\rightarrow 2x + 4 = 0\\\\\rightarrow 2x +4 - 4 = 0 - 4\\\\\rightarrow 2x = -4\\\\\rightarrow\frac{2x=-4}{2}\\\\\rightarrow \boxed{x=-2}

⸻⸻⸻⸻

\text{The \textbf{x-intercept} of the given equation is: } (-2, 0)

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

6 0
3 years ago
Clarisvaudney tem 12 anos. Seu primo é 50% mais novo.Qual é a soma da idade dos dois?
Nitella [24]
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8 0
3 years ago
The length of a violin string varies inversely with the frequency of its vibrations. A violin string 14 inches long vibrates at
lara31 [8.8K]

Answer: 525 cycles per second.

Step-by-step explanation:

The equation for inverse variation between x and y is given by :-

x_1y_1=x_2y_2       (1)

Given : The length of a violin string varies inversely with the frequency of its vibrations.

A violin string 14 inches long vibrates at a frequency of 450 cycles per second.

Let x =  length of a violin

y=  frequency of its vibrations

To find: The frequency of a 12 inch violin string.

Put x_1=14,\ x_2=12\\y_1=450,\ y_2=y in equation (1) , we get

(14)(450)=(12)(y)  

Divide both sides by 12 , we get

y=\dfrac{(14)(450)}{12}=525

Hence, the frequency of a 12 inch violin string = 525 cycles per second.

3 0
3 years ago
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