Answer:
smooth was dominant over that for wrinkled
Explanation:
In complete dominance, a gene may have two different variants or 'alleles', dominant and recessive. A dominant allele is a gene variant that is able to produce a certain phenotype, even in the presence of other alleles, while a recessive allele is a gene variant that is masked by the dominant allele in heterozygous individuals (i.e., individuals that inherited different alleles from each parent). By crossing smooth and wrinkled pea plants, Mendel observed the offspring (F1) were smooth rather than mixed, indicating one type of seed texture was dominant over the other. Subsequently, Mendel observed that alleles for different traits (e.g., seed texture and seed color) assorted independently during meiosis.
<h2>
Answer:</h2><h2>
<em>Root</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>the</em><em> </em><em>major</em><em> </em><em>parts</em><em> </em><em>of</em><em> </em><em>bulb</em><em>.</em></h2>
Explanation:
<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em> </em><em>y</em><em>o</em><em>u</em><em />
Answer:
we will know that the allelic frequencies are for R 0.95 and r 0.05
Explanation:
We know that the population is in Hardy-Winberg equilibrium, we deduce the following formula:
p + q = 1
p2 + 2pq + q2 = 1
data
R: red flower allele
r: allele blor blanca
p would be equal to the allelic frequency R
q will be equal to the frequency allelic r
2p = RR
2q = rr
2pq = Rr
If there are 25 white flowers in 1000 plants, their frequency will be:
2pq frequency of the Rr genotype
white flower = 25/10000 = 0.0025 = rr = 2q = 0.0025
we deduce that q is equal to 0.05
we replace the data with the previous formula
p + q = 1
p = 1-0.05
we get as a result
p = 0.95
if p = 0.95 and q = 0.05
we will know that the allelic frequencies are for R 0.95 and r 0.05
The doughnut because it contains carbohydrates
Trial and Error
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