What is 8c + 10b ÷ 7a if c = 7, b = 12, and a = 5 Please give a full and good explanation for a brainliest...
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See the attached figure to better understand the problem
we know that
1) First way to find the value of a
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²--------> BC²=AC²-AB²-----> BC²=25²-15²-----> BC²=625-225
BC²=400--------> BC=20 units
a=BC
a=20 units
2) Second way to find the value of a
in the triangle ABD
AB²=AD²+BD²--------> BD²=AB²-AD²-----> BD²=15²-9²---> BD²=144
BD=12 units
in the triangle BDC
a=BC
BC²=BD²+DC²-----> 12²+16²----> 144+256------> BC²=400
BC=20 units
a=20 units
we know that
1) First way to find the value of a
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²--------> BC²=AC²-AB²-----> BC²=25²-15²-----> BC²=625-225
BC²=400--------> BC=20 units
a=BC
a=20 units
2) Second way to find the value of a
in the triangle ABD
AB²=AD²+BD²--------> BD²=AB²-AD²-----> BD²=15²-9²---> BD²=144
BD=12 units
in the triangle BDC
a=BC
BC²=BD²+DC²-----> 12²+16²----> 144+256------> BC²=400
BC=20 units
a=20 units
I'll help with number 5 since number 4 is a bit too small and squished to read.
Check out the attached image below for the full two-column proof. The added entries are in red.
The given statement is basically what the teacher shows at the top of the problem, which is the fact that angle 5 and angle 2 are congruent. You just repeat this statement.
The reason for statement 2 is that angle 2 and angle 4 are vertical angles. They are opposite angles formed by a pair of intersecting lines. This is the vertical angle theorem at work. We'll use the vertical angle theorem again for statement 4 when we say that angle 5 and angle 8 are the same measure.
The transitive property comes into play when we connect angles 2, 5, and 4 together, which helps us get line 3. We also connect angles 4, 5 and 8 together to get the last line, which is why the reason for statement 5 is "transitive property"
Hi there!
Find the total area by breaking the figure into two rectangles, one trapezoid, and one triangle.
Rectangles:
A = l × w
A = 2.75 × 4 = 11 in²
Solve for the other rectangle's length by subtracting from the total:
12 - 2 - 3 - 4 = 3
A = 3 × 3 = 9 in²
Total rectangle area: 11 + 9 = 20 in²
Trapezoid:
A = 1/2(b1 + b2)h
A = 1/2(4.25 + 2.75)3 = 21/2 = 10.5 in²
Triangle:
A = 1/2(bh)
A = 1/2(2.5 · 2) = 2.5 in²
Add up all of the areas:
20 + 10.5 + 2.5 = 33 in²