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nekit [7.7K]
3 years ago
5

A region with a 5-mile radius has a population density of about 3100 people per square mile. Find the number of people who live

in the region to the nearest ten thousand
Mathematics
1 answer:
Gwar [14]3 years ago
4 0

Answer:

243,000 people

Step-by-step explanation:

First, what we need to do is to calculate the area of the region using the 5-mile radius

Mathematically, we can calculate this as the area of a circle

Area = pi * r^2

Our r here is 5 miles

Area = pi * 5^2 = pi * 25 = 78.54 square miles

Now to get the population, we know that per square mile we have 3,100.

Hence per 78.54 square mile, we have 78.54 * 3100 = 243,273 people

To the nearest thousand, 243,000

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What is the answer to this math problem​
vesna_86 [32]

Hello from MrBillDoesMath!

Answer:

1/243

Discussion:  

3^(-3) *  3^(-2)                => as a^m * a^n = a^(m+n), the exponents add

= 3^ (-3 -2)

= 3^ (-5) =

= 1/ 3^5                           => as 3^5 = 243

= 1/243

which is approximately  .0041

Thank you,

MrB

7 0
4 years ago
Read 2 more answers
Find the value of y when x equals -1.<br><br> 8x - 2y =10
Artyom0805 [142]

Answer:

y = - 9

Step-by-step explanation:

Substitute in -1 for x

8(-1) - 2y = 10

-8 - 2y = 10

Subtract -8 from both sides

-8 - (-8) cancels out to 0

10 - (-8) = 18

We are left with:

-2y = 18

Divide by -2 on both sides.

-2y/-2 = y

18/-2 = -9

y = -9

6 0
3 years ago
Darla is taking a survey at her school. She finds that 20 out of 100 students have fish as pets. This means that her experimenta
Arisa [49]

Answer:

The second option

Step-by-step explanation:

This is because the more samples she has, the closer her experimental probability will be to the real value.

6 0
4 years ago
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
Common household electric current is called alternating current because the current alternates direction within the wires. The v
Rainbow [258]

Answer:

n = 18 cycles

Step-by-step explanation:

To know how many times does the current oscillates in the given time, you take into account that the number of oscillation can be calculated by using the following expression:

n=ft         (1)

f: frequency of the oscillation of the current

t: time = 0.30s

The frequency is the number of cycles per second, that is, f = 60 cycles/s

You replace the values of f and t in the equation (1):

n=(60\frac{cycles}{s})(0.30s)=18\ cycles

In 0.30s the current oscillates 18 times

5 0
3 years ago
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