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Gelneren [198K]
3 years ago
10

Rolf spent 15 hours last week practicing his saxophone. If 3/10 of the time was spent practicing warm up routines, how much time

did he spend practicing warm up routines
Mathematics
1 answer:
agasfer [191]3 years ago
4 0
Four point five (4.5)
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Help me please<br>i need help
DerKrebs [107]

Answer:

1.300


Step-by-step explanation:


5 0
3 years ago
62 = 9z + 17<br> Solve for Z
Lina20 [59]

Answer : Z = 5

Step-by-step explanation :

62 = 9z + 17

-17 -17

45 = 9z

/9 /9

5 = z

Plug it back in :

62 = 9(5) + 17

62 = 45 + 17

62 = 62

7 0
3 years ago
Which test point holds true for the inequality 3/2y-2x&gt;=1? Where does the shaded area lie for this inequality? The test point
Tanya [424]

The test That holds true for this inequality is given as 1/4 and 1

<h3>How to solve for the inequality</h3>

3/2 y - 2x > 1

The goal is to make y the subject

then

3/2 y > 2x + 1

We have to divide through the equation by 3/2

Such that  y  > 4/3 x + 2/3

Read more on inequality here: brainly.com/question/25275758

#SPJ1

8 0
2 years ago
Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
3 years ago
Read 2 more answers
Difference between purchase book and sales book​
tigry1 [53]
A purchase is one where you purchase it and sales is one you sell :)

Hope that helped!
4 0
4 years ago
Read 2 more answers
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