Question

An airplane started at point K, travelled 560 miles to point L, adjusted its route and travelled another 575 miles to point M. If the airplane is currently 952 miles from its starting position at point K, by how many degrees did it adjust its route at point L

Answer 1

Answer:

Step-by-step explanation:

Using the cosine theorem:

$c^{2} =a^{2} +b^{2} -abcos\beta$

$952^{2} =560^{2} +575^{2} -560*575cos\beta$

$\beta =cos^{-1} (\frac{560^{2}+575^{2}-952^{2} }{2*560*575} )$

The angle is 114.014 degrees if we substract 90 degrees it means that at point L the plane changed its angle by 24 degrees