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katrin2010 [14]
3 years ago
10

Solve -17-2(×-4)-5(4×-7)

Mathematics
1 answer:
mina [271]3 years ago
8 0
26-22x is the correct answer
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2. JI. has coordinates J(-6, 1) and Z(-4, 3). Find the coordinates of the midpoint.​
AleksandrR [38]

Answer:

(- 5, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \frac{x_{1}+x_{2}  }{2}, \frac{y_{1}+y_{2}  }{2} )

Here (x₁, y₁ ) = (- 6, 1) and (x₂, y₂ ) = (- 4, 3) thus

midpoint = \frac{-6-4}{2}, \frac{1+3}{2} ) = ( \frac{-10}{2}, \frac{4}{2} ) = (- 5, 2 )

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3 years ago
I need help fast can someone please help
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Use the functions f(x) = 4x² + 3 and g(x) = 3x + 2 to evaluate the following.
natita [175]

Answer:

Step-by-step explanation:

f(-2)= 4(-2)^2 + 3 = 4(4) + 3 = 16 + 3 = 19

g(19) = 3(19) + 2 = 57 + 2 = 59

g(-2)= 3(-2) + 2 = -6 + 2 = -4

f(-4)= 4(-4)^2 + 3 = 64 + 3 = 67

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2 years ago
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Step-by-step explanation:

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Expand and simplify 5(3x+2)-2(4x-1)
blsea [12.9K]

5(3x+2)-2(4x-1)

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