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3 years ago

What time what give me 21

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

8 0

21:00 would be 9:00 :)

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Find the value of x such that the data set has a mean of 103.<br><br> 99,122,103,113,109,x

Mashcka [7]

That means the average of all data point equal:

(99+122+103+113+109+x)/6 = 103
===> (546+x)/6 = 103===> 546+x=618 & x=618-546=72, so x =72

8 0

3 years ago

What is the angle of rotation of the image?<br>A. 60°<br>B. 90°<br>C.120°<br>D. 180°<br>

lisov135 [29]

Answer:

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3 years ago

The function h(t) = −5t2 + 25t shown in the graph models an architectural arch:

alukav5142 [94]

Answer:

the answer is actually 0 ≤ x ≤ 5

Step-by-step explanation:

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3 years ago

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

$(a^m)^n = a^{m\times n}$

$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

5 0

2 years ago

Read 2 more answers

Cotθ= tan30° find theta

scoundrel [369]

Answer:

Step-by-step explanation:

Cot is the same as 1/tan so:

$1/tan(theta) = tan(30)$

By rearranging the equation, we get:

$1/tan(30) = tan(theta)$

By taking the inverse tan, we get:

$theta = tan^-1 (1/tan(30)) =60$

7 0

2 years ago