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3 years ago

15

If a fair-number cube with sides numbered from 1 to 6 is tossed 240 times, approximately how many times would the fair-number cu

be land on a number that is greater than 2?

1 answer:

LenKa [72]3 years ago

8 0

It wouls be greater 50times

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qwelly [4]

Answer:

x = 0

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4 0

3 years ago

Y= - x+2 Y=3x-4<br> Estimate the solution to the system of equations

IrinaVladis [17]

Answer:

$x=\frac{3}{2}\\ y=\frac{1}{2}$

Step-by-step explanation:

$y=-x+2\\y=3x-4$

Let's solve one of them for x.

$y=3x-4$

Add 4

$y+4=3x$

Divide by 3.

$x=\frac{y+4}{3}$

Now, plug the value of y in the formula, or you can plug the value of x in the other equation. I'll take this one.

$x=\frac{y+4}{3}$

$x=\frac{(-x+2)+4}{3}$

$x=\frac{-x+2+4}{3}$

$x=\frac{-x+6}{3}$

Multiply by 3 to get rid of the denominator.

$3x=-x+6$

add x

$3x+x=6$

Combine like terms;

$4x=6$

Divide by 4.

$x=\frac{6}{4}$

Simplify.

$x=\frac{3}{2}$

Now that you found the value of x, replace it in any of the equations to find y.

$y=-x+2\\y=-(\frac{3}{2})+2\\ y=-\frac{3}{2}+2$

$y=\frac{-3+2*2}{2} \\y=\frac{-3+4}{2} \\y=\frac{1}{2}$

Proof:

$y=3x-4\\\frac{1}{2}=3(\frac{3}{2})-4\\\frac{1}{2}=(\frac{9}{2})-4$

$\frac{1}{2}=\frac{9-4*2}{2}$

$\frac{1}{2}=\frac{9-8}{2}$

$\frac{1}{2}=\frac{1}{2}$

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(40+41+41+45+48+48+49+49+49+40)/10 = 460/10 = 46

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