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4vir4ik [10]
3 years ago
15

If a fair-number cube with sides numbered from 1 to 6 is tossed 240 times, approximately how many times would the fair-number cu

be land on a number that is greater than 2?
Mathematics
1 answer:
LenKa [72]3 years ago
8 0
It wouls be greater 50times
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Ariana and tom Tabitha recorded the amount of time spent on homework on 10 school daze graph of the data are shown
Sedaia [141]

Answer:

theres no picture

Step-by-step explanation:

5 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
Help me on the last two Plzzzzzz!!! will give brainliest
Musya8 [376]
<h2><em>Well for the Table, the last 2 numbers are 65 and 80. The Hourly Rate is +15. Not sure about the fees or the top one.</em></h2>
3 0
3 years ago
Can you please help
Novosadov [1.4K]

Answer:

Fill in the answers from the first box to the second box.

Step-by-step explanation:

The picture is hard to see so I'm not 100% sure but I think you just fill in the data from the first table to the second one. For example, if the first table says 15 under morning and for whales, you type 15 in that spot on the second one. Hopefully that helped :)

8 0
2 years ago
1. (section 2.1) Bungee jumping: Jimmy jumped off the Tallahatchie Bridge, 100 ft above
Tems11 [23]

Answer:

18.4 ft per second.

Step-by-step explanation:

Bungee jumped off the Tallahatchie Bridge, which is 100 ft above the water surface.

And after 5 seconds he was at 8 ft above the water surface.

Therefore, in total 5 seconds, he descends by total ( 100 - 8 ) = 92 ft altitude.

Hence, the average rate of change of his altitude is given by  

\frac{\textrm{Total altitude change}}{\textrm{Total time taken}} = \frac{92}{5} =18.4 feet per seconds. (Answer)

7 0
3 years ago
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