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2 years ago

15

If a fair-number cube with sides numbered from 1 to 6 is tossed 240 times, approximately how many times would the fair-number cu

be land on a number that is greater than 2?

1 answer:

LenKa [72]2 years ago

8 0

It wouls be greater 50times

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3 years ago

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2 years ago

(10-i)-(12+6i)<br> .............

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3 years ago

Read 2 more answers

verifica care dintre urmatoarele numere sunt cuburi perfecte:2 la puterea a 8, 27, 64, 5 la puterea 48, si 7 la puterea 225

4vir4ik [10]

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Step-by-step explanation:

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2 years ago

Helppppppp! 15 points!

Vika [28.1K]

${\boxed{\mathcal{\purple{D.\:81}}}}$ ✅

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( {3})^{ \frac{11}{5} } \div {3}^{ \frac{ - 9}{5} } \\ \\=( {3})^{ \frac{11}{5} - ( \frac{ - 9}{5} ) } \\ \\ = ( {3})^{ \frac{11}{5} + \frac{9}{5} } \\ \\ = ( {3})^{ \frac{11 + 9}{5} } \\ \\ = ( {3})^{ \frac{20}{5} } \\ \\ = ( {3})^{4} \\ \\ = ( \: 3 \times 3 \times 3 \times 3 \: ) \\ \\ = 81$

<u>Note</u>:-

${a}^{m} \div {a}^{n} = {a}^{m - n}$

$\sf\red{(-)\:x\:(-)\:=\:+}$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}$

4 0

2 years ago