Does a linear equation have no solution, one solution, or infinitely many solutions?
2 answers:
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Only apply formula. Hope it helped.
We have that
<span>f(x) = (3/2)*x + 4
case 1) for x=-8
</span>f(-8) = (3/2)*(-8) + 4--------> -8
point (-8,-8)
case 2) for x=-4
f(-4) = (3/2)*(-4) + 4--------> -2
point (-4,-2)
case 3) for x=-2
f(-2) = (3/2)*(-2) + 4--------> 1
point (-2,1)
case 4) for x=0
f(0) = (3/2)*(0) + 4--------> 4
point (0,4)
case 5) for x=2
f(2) = (3/2)*(2) + 4--------> 7
point (2,7)
case 6) for x=4
f(4) = (3/2)*(4) + 4--------> 10
point (4,10)
using a graph tool
see the attached figure
<span>f(x) = (3/2)*x + 4
case 1) for x=-8
</span>f(-8) = (3/2)*(-8) + 4--------> -8
point (-8,-8)
case 2) for x=-4
f(-4) = (3/2)*(-4) + 4--------> -2
point (-4,-2)
case 3) for x=-2
f(-2) = (3/2)*(-2) + 4--------> 1
point (-2,1)
case 4) for x=0
f(0) = (3/2)*(0) + 4--------> 4
point (0,4)
case 5) for x=2
f(2) = (3/2)*(2) + 4--------> 7
point (2,7)
case 6) for x=4
f(4) = (3/2)*(4) + 4--------> 10
point (4,10)
using a graph tool
see the attached figure