CD = x
BC = y
AB = 85
BD = BC+CD = y+x
tan(angle) = opposite/adjacent
tan(28) = BC/AB
tan(28) = y/85
85*tan(28) = y
y = 85*tan(28)
y = 45.1953016912257
tan(angle) = opposite/adjacent
tan(31) = BD/AB
tan(31) = (y+x)/85
tan(31) = (45.1953016912257+x)/85
85*tan(31) = 45.1953016912257+x
51.0731526173427 = 45.1953016912257+x
51.0731526173427-45.1953016912257 = 45.1953016912257+x-45.1953016912257
5.877850926117 = x
x = 5.877850926117
So CD is roughly 5.877850926117 meters
Answer:
The number of child tickets sold by the amusement park is 189.
Step-by-step explanation:
Let A represent the number of adult tickets and C represents the number of child tickets, therefore we have:
3:1 = C:A .................... (1)
Where;
C = ?
A = 63
Substituting for the value into equation (1), we have:
3:1 = C:63
This can be converted to solve for C as follows:
3 / (3 + 1) = C / (C + 63)
3 / 4 = C / (C + 63)
0.75 = C / (C + 63)
0.75(C + 63) = C
0.75C + (0.75 * 63) = C
0.75C + 47.25 = C
47.25 = C - 0.75C
47.25 = 0.25C
C = 47.25 / 0.25
C = 189
Therefore, the number of child tickets sold by the amusement park is 189.
Answer:
Probability that the calculator works properly for 74 months or more is 0.04 or 4%.
Step-by-step explanation:
We are given that the life span of a calculator has a normal distribution with a mean of 60 months and a standard deviation of 8 months.
Firstly, Let X = life span of a calculator
The z score probability distribution for is given by;
Z = 
~ N(0,1)
where, 
= population mean = 60 months
= standard deviation = 8 months
Probability that the calculator works properly for 74 months or more is given by = P(X 
74 months)
P(X 74) = P( 
) = P(Z 1.75) = 1 - P(Z < 1.75)
= 1 - 0.95994 = 0.04
Therefore, probability that the calculator works properly for 74 months or more is 0.04 or 4%.
