The answer to this problem is 5x-4
answer.
Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
5x+2y=105x+2y=10 (1)
And 3x+2y=63x+2y=6 (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
15x+6y=3015x+6y=30 (3)
15x+10y=3015x+10y=30 (4)
Now subtract (4) from (3) we get:
-4y=0−4y=0
y=0y=0
Now, put y=0 in (1) equation:
5x+2(0)=105x+2(0)=10
5x=105x=10
x=2x=2
Hence, x=2 and y=0
I would say 32, just from doing PEMDAS.
Answer: C
Step-by-step explanation:
Y=a(x-1)^2 -17 is the equation of the parabola.
at (0,16), 16=a(0-1)^2 -17. Solve for a = 33.
Equation is then y=33(x-1)^2-17 so when y=0,
(x-1)^2 = 17/33
x-1 = + and - square root of 17/33
x = 1.7177 and 0,2823 as the intercepts
