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maxonik [38]
3 years ago
7

A bag contains 17 cards numbered 1 through 17 . a card is randomly chosen from the bag. what is the probability that the card ha

s an even number on it? write your answer as a fraction in simplest form.
Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0

Probability of choosing a card that has an even number on it = \frac{8}{17}

<em><u>Explanation </u></em>

<u>Cards:</u> 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

There are total 17 cards and we are choosing only one card randomly which has even number on it.

<em>The even number cards are: </em>2 4 6 8 10 12 14 16

That means there are total 8 even number cards.

So, Probability of choosing a card that has an even number on it = \frac{8}{17}

Strike441 [17]3 years ago
6 0
Solution:

Even number:
2, 4, 6, 8, 10, 12, 14, 16
TOTAL: 8

Therefore,
Probability = 8/17
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ira [324]

<u>Answer:</u>

• mean = 61

• mode = 50

• median = 57.5

<u>Step-by-step explanation:</u>

• The mean is calculated by adding all the values together, and dividing the result by the number of values.

∴ mean =  \frac{60 + 50 + 50 + 70 + 40 + 80 + 65 + 55 + 50 + 90}{10}

⇒ mean = \frac{610}{10}

⇒ mean = 61

• The mode of a set of values is the value that is the most common (has highest frequency) among them.

50 is the most common value.

∴ mode = 50

• The median is the middle-value of a set of ordered values.

∴ We have to first rearrange the set:

⇒  40, 50, 50, 50, 55, 60, 65, 70, 80, 90

Now we need to find the middlemost value:

Since we have 10 values, which is an even number, we have to use the formula:

median = \frac{(n/2)^{th} \space\ term  \space\ + \space\ [(n/2) + 1]^{th} \space\ term  }{2}

where n is the number of values.

∴ median =  \frac{(10/2)^{th} \space\ term  \space\ + \space\ [(10/2) + 1]^{th} \space\ term  }{2}

⇒ median =  \frac{5^{th} \space\ term  \space\ + \space\ 6^{th} \space\ term  }{2}

The 5th and 6th terms in our ordered series are 55 and 60 respectively.

∴ median = \frac{55 + 60}{2}

⇒ median = 57.5

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2 years ago
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Answer:

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