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Vilka [71]
2 years ago
10

Are these two claims equivalent, in conflict, or not comparable because they're talking about different things? a. "Every year s

ince 1950, the number of American children gunned down has doubled." b. "The number of child gunshot deaths has doubled from 1950 to 1994."
Mathematics
1 answer:
KATRIN_1 [288]2 years ago
4 0
B 1995-1998











Hope this helps
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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
Rzqust [24]

Answer:

a = 6 or 9

Step-by-step explanation:

The "a", "b", and "c" of the quadratic formula are the coefficients of a², a, and the constant term in the given equation:

... a = 2, b = -30, c = 108

Then the quadratic formula tells you the solutions are ...

... (-b ± √(b² -4ac))/(2a)

... = (-(-30) ± √((-30)² -4(2)(108)))/(2(2))

... = (30 ± √(900 -864))/4

... = (30 ± √36)/4

... = (30 ± 6)/4 = {24, 36}/4

... = {6, 9}

_____

The <em>a</em> variable should not be confused with the "a" that is used to name the coefficient of the square of the variable in the quadratic formula. If it is too confusing, rewrite one or the other. For example, you could write ...

... The solution to pa² +qa +r = 0 is ... a = (-q ± √(q²-4pr))/(2p)

where p=2, q=-30, r=108 in the given equation.

5 0
3 years ago
Round 80531 to the nearest thousand.
Iteru [2.4K]
That would be 8,1000
6 0
3 years ago
Read 2 more answers
5x+9−2x+13=67 solve the equation
MariettaO [177]

Answer:

5x+9−2x+13=67

3x+9+13=67

3x+22=67

3x=45

x=15

Mark brainliest!!

3 0
2 years ago
Read 2 more answers
Simplify (x^2)^3*5x/6x^2*15x^3
nasty-shy [4]

When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>
  • [(x^2)^3 × 5x] / [6x^2 × 15x^3]
  • Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

  • [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

Learn more about algebra:

brainly.com/question/2768008

#SPJ1

8 0
1 year ago
At a local fitness center, members pay a $10 membership fee and $5 for each aerobics class. Nonmembers pay $6 for each aerobics
Burka [1]

Answer:

10 aerobic classes

Step-by-step explanation:

For non- members:

10 x 6 = $60

For members:

10 x 5 = $50 + $10 (Membership fee) = $60

7 0
3 years ago
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