What is the distance from the origin to point A graphed on the complex plane below?

What is the solution to the system of equations below?

disa [49]

The solution to the system of equation are x=2, y=0, z=6

<h3>System of equations</h3>

System of equations are equations that contains unknown variables.

Given the equations

3x+y+2z=8

8y+6z=36

12y+2z=12

From equation 2 and 3

8y+6z=36 * 1

12y+2z=12 * 3

______________

8y+6z=36

36y+6z= 36

Subtract

8y - 36y = 36 - 36

-28y =0

y = 0

Substitute y = 0 into equation 2

8(0)+6z=36

6z = 36

z = 6

From equation 1

3x+y+2z =8

3x + 0 + 2(6) = 8

3x = 8 - 12

3x = 6

x = 2

Hence the solution to the system of equation are x=2, y=0, z=6

Learn more on system of equation here: brainly.com/question/14323743

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3 0

2 years ago

For the function y = 3x^2 - 12x + 4, what is the mirror point for the y-intercept? Give your answer in (x,y) point form.

saveliy_v [14]

Answer:

Your in Pacyber aren't you? Mr. Breux class? Anyway the answer is (0,-4)

Step-by-step explanation:

The y intercept is (0,-4)

6 0

3 years ago

What is every number in pie? please put all numbers!

Mila [183]

Answer: The number pi is an irrational number

Step-by-step explanation:

Pi is irrational because it will never end and at the same time doesnt have a pattern in which the numbers repeat. Here are some of the numbers in pi 3.14159265359

8 0

3 years ago

Sam has 35 rubbers.He wants to share them equally between 3 of his friends .How many will each friend receive?How many are left

Nitella [24]

Answer:

11 will be shared out and there will be 2 rubbers left.

Step-by-step explanation:

the last number that 3 goes into before 35 is 33. 33 ÷ 3 = 11. So each friend gets 11 rubbers. then from 33, there will be 2 rubbers left.

5 0

3 years ago

Find a function where f(0)=2 and f(1)=2

xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

$f(x) = x^2-x+2$

Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need $A= 2$ , and at that point the first condition is guaranteed; using the second to find k we get $2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi$

$f(x) = 2cos(2\pi x)$

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

$f(x)= 2+sin(2\pi x)$

Sky is the limit.

8 0

3 years ago