Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
3
Step-by-step explanation:
1926/9=214
1923+3=1926
Answer:
Volume of the cube = (2n6)³
Step-by-step explanation:
Volume of a cube = L*B*H
Volume of a cube= L*L*L=L³ (since all the sides of the cube are equal.
Volume of the cube = (2n6)³
Answer:
Step-by-step explanation:
If they can be rounded to 70 to the nearest 10s. Then they are from 65 to 74.
Their sum is 136.
If we use 136 divided by 2 we get 68.
Since they're distinct, so one can be 67 and one can be 69
Answer: A section of something
Step-by-step explanation: A section of something