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krek1111 [17]
3 years ago
13

Simplify: √27 A. 3√3 B. 9√3 C. 3√9 D. 5√3

Mathematics
1 answer:
blagie [28]3 years ago
5 0
To simplify square root 27, find two numbers that equal 27. But also, one of the numbers should be a perfect square (such as 4, 9, 36...). 

9*3=27. The square root of 9 is 3, which makes it a perfect square. So, the answer is A.
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Use cramers Rule to solve the following system:
Jet001 [13]

Answer:

The solution to the system is x=1,y=-2 and z=-5

Step-by-step explanation:

Cramer's rule defines the solution of a system of equations in the following way:

x= \frac{D_x}{D}, y= \frac{D_y}{D} and z= \frac{D_z}{D} where D_x, D_y and D_z are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively. D is the determinant of the system. Let's see how this rule applies to this system.

The system can be written in matrix form like:

\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]

Then each of the previous determinants are given by:

D_x = \left|\begin{array}{ccc}6&-3&1\\11&2&-3\\-13&10&0\end{array}\right|=199 Notice how the x-column has been substituted with the answer-column one.

D_y = \left|\begin{array}{ccc}5&6&1\\0&11&-3\\7&-13&0\end{array}\right|=-398 Notice how the y-column has been substituted with the answer-column one.

D_z = \left|\begin{array}{ccc}5&-3&6\\0&2&11\\7&10&-13\end{array}\right|=-995

Then, substituting the values:

x= \frac{D_x}{D}=\frac{199}{199}\\ x=1

x= \frac{D_y}{D}=\frac{-398}{199}\\ y=-2

x= \frac{D_z}{D}=\frac{-995}{199}\\ x=-5

3 0
3 years ago
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