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3 years ago

Simplify: √27 A. 3√3 B. 9√3 C. 3√9 D. 5√3

1 answer:

5 0

To simplify square root 27, find two numbers that equal 27. But also, one of the numbers should be a perfect square (such as 4, 9, 36...).

9*3=27. The square root of 9 is 3, which makes it a perfect square. So, the answer is A.

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MaRussiya [10]

Answer:

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Step-by-step explanation:

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3 years ago

Question 10

julia-pushkina [17]

Answer:

c use your brain ok

Step-by-step explanation:

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7 0

3 years ago

@Apologiabiology mind helping once more?

Kisachek [45]

Domain is all real, yep
vertex of y values is from2 to infinity, so 2nd is false
y int is where x=0, that is at y=2, nope so 3rd is false
2 up and 1 to left, so no for 4th
x intercept? there are none

answer is only first option

6 0

3 years ago

What is the value of a in the equation a = 2 + 3a + 10?

xxTIMURxx [149]

Answer:

a= -6

Step-by-step explanation:

Given

a=2+3a+10

In order to find the value of a, we have to isolate a on a single side of the equation

So,

subtracting 3a from both sides

a-3a = 2+10+3a-3a

=>a-3a=12

=> -2a = 12

Dividing both sides by -2

=> -2a/-2 = 12/-2

=> a = -6

The value of a in the given equation is -6 ..

3 0

3 years ago

PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS

Elina [12.6K]

You want to end up with $A\sin(\omega t+\phi)$ . Expand this using the angle sum identity for sine:

$A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi$

We want this to line up with $2\sin(4\pi t)+5\cos(4\pi t)$ . Right away, we know $\omega=4\pi$ .

We also need to have

$\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}$

Recall that $\sin^2x+\cos^2x=1$ for all $x$ ; this means

$(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}$

Then

$\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)$

So we end up with

$2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)$

8 0

3 years ago

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