the probability of rolling 4 or a number less than 6 is P = 5/6
<h3 /><h3>How to find the probability?</h3>
The standard number cube has the outcomes {1, 2, 3, 4, 5, 6}
We want to find the probability of rolling 4 or a number less than 6. (4 is a number less than 6).
The outcomes that meet that condition are:
{1, 2, 3, 4, 5}
So 5 out of 6 outcomes meet the condition, then the probability is:
P(4 or less than 6) = 5/6
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The answers are 3/8 and 1/6.
There are 8 possible outcomes in the sample space for flipping 3 coins. Of those, 3 include two heads and 1 tail. This makes the probability 3/8.
Choosing a quarter for the first coin is 3/10, since there are 3 quarters out of 10 coins. After this, choosing a dime is given by 5/9, since there are 5 dimes out of 9 coins left:
3/10(5/9) = 15/90 = 1/6
Answer:
-1.
Step-by-step explanation:
1/m = m^-1.
We can show this is correct if we simplify the following:
m^2 / m ^3 = m * m / m * m* m = 1/m
By the law of indices: m ^2 / m^3 = m^(2-3) = m^-1.
Answer:
f(x, y) = Sin(x*y)
We want the second order taylor expansion around x = 0, y = 0.
This will be:

So let's find all the terms:
Remember that:


f(0,0) = sin(0*0) = 1.





Then we have that the taylor expansion of second order around x = 0 and y = 0 is:
sin(x,y) = x*y + x*y + x*y = 3*x*y