Find MN LM = 3y + 4 MN = 7y + 9 LN = 143
1 answer:
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Since the graph is a straight line, its equation is of the form;
Where m is the slope and c is the y intercept
We can use any two points on the straight line to find the value of m and c.
Let us use (0,30) and (4,150)
This simplifies to,
Let us substitute the value of m to obtain,
Substitute any of the points to find c. It is easier to use (0,30).
The equation of the graph now becomes,
So in 10 weeks Ben will collect,
Ben will collect 330 papers.
You can also use any two points to find the equation of this line.
Where m is the slope and c is the y intercept
We can use any two points on the straight line to find the value of m and c.
Let us use (0,30) and (4,150)
This simplifies to,
Let us substitute the value of m to obtain,
Substitute any of the points to find c. It is easier to use (0,30).
The equation of the graph now becomes,
So in 10 weeks Ben will collect,
Ben will collect 330 papers.
You can also use any two points to find the equation of this line.
Answer:
Step-by-step explanation:
Hello!
There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:
D1 ⇒ P(D1)= 0.15
D2 ⇒ P(D2)= 0.25
D3 ⇒ P(D3)= 0.40
D4 ⇒ P(D4)= 0.20
Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:
P(E1)= 0.01
P(E2)= 0.02
P(E3)= 0.01
P(E4)= 0.02
Ei is then the event that "the piece was printed by Di" and "the piece is defective".
You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)
Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:
P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06
This is a conditional probability and you can calculate it as:
To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.
P(D1∩E)= P(E1)= 0.01
P(D2∩E)= P(E2)= 0.02
P(D3∩E)= P(E3)= 0.01
P(D4∩E)= P(E4)= 0.02
Now you can calculate the probability of the piece bein printed by each printer given that it is defective:
P(D2)= 0.25 and P(D2/E)= 0.33 ⇒ The prior probability of D2 is smaller than the posterior probability.
The fact that P(D2) ≠ P(D2/E) means that both events are nor independent and the occurrence of the piece bein defective modifies the probability of it being printed by the second printer (D2)
I hope this helps!
Answer:
C
Step-by-step explanation:
I think I will answer the question the your attachment because it has full information.
The function is: y = 3*
a. The function decreases
Wrong, because the base number is 2 and it is greater than 0. The function will go up
b. y=intercept of (0.2)
Wrong, Let substitute x =2 into the function: y = 3* = 12
c. if x increase by 1, the value of y will double
Because the base number is 2. For example:
- If x = 2, y = 3*
= 12
- If x =3, y =3*
=(3*
d. contains the point (2,4)
Wrong, Let substitute x =4 into the function: y = 3* = 48
So we choose C