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Given:
r = radius = 4
h = height = 12
dr = error in radius = 0.2
What we want to find
dV = error in volume
Use the derivative to find the differential dV
V = pi*r^2*h
dV/dr = d/dr[ pi*r^2*h ]
dV/dr = 2pi*r*h
dV = 2pi*r*h*dr
dV = 2pi*4*12*0.2
dV = 19.2pi
So if the error in measuring the radius is +-0.2 inches, then the error in the cylinder volume is +-19.2pi cubic inches (we either measure the volume to be 19.2pi cubic inches too big, or 19.2pi cubic inches too small)
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Final Answer: Plus or minus 19.2pi cubic inches
Note: your teacher may want you to drop the "plus or minus" part
Answer:
1. A. 4 terms
There are 4 different values in the expression, so therefore there are 4 terms.
2. D. 3x^2 + 6x + 10
To get the answer...
start with the original expression: 3x^2 + x + 10 + 5x
add the like terms together, in this case you'd add x + 5x
you'll get: 3x^2 + 6x + 10
I hope I could help :)