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3 years ago

Find the y? 3x + 6y = 12

Mathematics

1 answer:

kari74 [83]3 years ago

5 0

Could you give Brainliest please???

Answer:

y = 2 - 1/2x

Step-by-step explanation:

So we are given the equation 3x + 6y = 12 and are ask to find y.

To find y you must isolate it first.

3x + 6y = 12

(Subtract 3x to isolate the y term)

6y = 12 - 3x

(Divide both sides by 6 to isolate the variable)

y = 2 - 3/6x

(Simplify)

y = 2 - 1/2x

And that is your answer since there is a second variable.

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What is the solution to the equation x/3+x/6=7/2

nadezda [96]

Answer:

x = 7

Step-by-step explanation:

the smallest common denominator between 2 3 and 6 is 6. Multiply the original equation by 6

6(x/3 + x/6 = 7/2)
6(x / 3) = 2x
6(x/6) = x
6(7/2) = 3*7 = 21

Result

2x + x = 21
3x = 21
3x/3 = 21/3
x = 7

Check

7/3 + 7/6 = 7/2
14/6 + 7/6 = ? 7/2
21/6 =? 7/2
21/6 = 3.5
7/2 = 3.5

Answer: x = 7

3 0

3 years ago

Find the measure of the arc for abc

Luda [366]

Answer:

124

Step-by-step explanation:

360 - (90+146) = 124

5 0

3 years ago

Solve the system by graphing.<br> 19) y = x2 + 2x + 7<br> y = 3x – 4

Sedbober [7]

Answer:

no real solutions

complex solutions: x = 0.5±i√10.75, y = -2.5±i·3√10.75

Step-by-step explanation:

The graph shows the line and parabola do not intersect, so there are no real solutions to this system of equations.

However, the complex x-solutions can be determined from the graph to be ...

x = 0.5 ±i√10.75

The corresponding y-values can be found from the equation

y = 3x -4 = 3(0.5 ±i√10.75) -4

y = -2.5 ± i·3√10.75

8 0

3 years ago

Solve for x in this equation: 3/4+|5-x|=13/4

m_a_m_a [10]

The answer is -5/7
Find the lcm of the denominator
And then use the lcm to multiple

6 0

3 years ago

Please help asap 20 pts + brainliest to right/best answer

AleksAgata [21]

Answer:

(-1,-2)

Step-by-step explanation:

The vertex of the parabola is the minimum or maximum point of the parabola. It is located along the line of symmetry.

Looking at the graph, the minimum point is (-1,-2)

5 0

4 years ago