Lea buys 20 picture frames. Some are 4 in. by 6 in. frames which cost $5.80 each, and the rest are 5 in. by 7 in. frames that co
1 answer:
To find the answer we have to slowly analyze the command.
For surely on the one side we want to have total cash spent, so 80.8$
We know that there are 2 types of frames 5,80$ and 9.60$.
We know too, that f is the number of frames 5.80$ bought.
Simply, to find the cash spent on those frames we have to just mulitply 5.80$ times f, so we obtain
.
We can say that number of bigger frames is 20-f.
So to find cash spent on bigger frames we have to multiply 9.60$ times (20-f), so
Now we can just add cost of all frames together
And we know that is equal to 80.8, so
=80.8
As we can see, the answer is b.
For surely on the one side we want to have total cash spent, so 80.8$
We know that there are 2 types of frames 5,80$ and 9.60$.
We know too, that f is the number of frames 5.80$ bought.
Simply, to find the cash spent on those frames we have to just mulitply 5.80$ times f, so we obtain
We can say that number of bigger frames is 20-f.
So to find cash spent on bigger frames we have to multiply 9.60$ times (20-f), so
Now we can just add cost of all frames together
And we know that is equal to 80.8, so
As we can see, the answer is b.
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Given:
The sequence is defined as "triple v, then subtract 7 from the result".
To find:
The expression for the given sequence.
Solution:
Triple v means 3 times of v, i.e., 3v.
So, the result is 3v.
Then subtract 7 from the result. So, the expression for the sequence is
Therefore, the required expression is .