21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Here you go pall, have a nice day
Answer:
49/12=4 1/12
Step-by-step explanation:
7/3+7/3=28/12+21/12=49/12=4 1/12
Answer:
D
Step-by-step explanation:
We observe that the values of m are 10 less than the corresponding values of n, that is
n = 10 → m = 10 - 10 = 0
n = 12 → m = 12 - 10 = 2
n = 15 → m = 15 - 10 = 5
n = 19 → m = 19 - 10 = 9
In general
m = n - 10 → D
