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Mademuasel [1]
2 years ago
10

Suppose you invest $1500 add an annual interest of 6.9% compounded continuously. How much will you have in the account after 10

years?
A. 14,952.87
B. 29,905.73
C. 2,990.57
D. 1,607.15

Mathematics
1 answer:
mojhsa [17]2 years ago
8 0

This is the answer. Hope it helps you☺

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Answer the following questions please.<br><br> Urgent.
djverab [1.8K]

Answer: What is the questions

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is the IQR (interquartile range) of the data set? 33, 37, 45, 61, 64, 67
Nataly_w [17]

solution is first os all find median

median is( 45+61)/2=53

find median of no in left of 53

it is 37

find median of no in right of 53

it is 64

now interquartile range=64-53=27

4 0
3 years ago
Please help me 33/2 + 3y/5 = 7y/10 + 15
8090 [49]

We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!

We are given with ;

{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}

Take LCM on both sides :

{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}

<em>Multiplying</em> both sides by <em>10</em> ;

{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}

{:\implies \quad \sf 165+6y=7y+150}

Can be <em>further written</em> as ;

{:\implies \quad \sf 7y+150=165+6y}

Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

{:\implies \quad \sf 7y-6y=165-150}

{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}

8 0
2 years ago
in sports club there are 800 members . the ratio of soccer members to social members is 5to 3 how many soccer players are there
attashe74 [19]
5:3

5+3=8
8 units

800=8 units
divide oth sides by 8
100=1 units

soccer=5 units=5 times 100=500
social=3 units=3 times 100=300



500 soccer players

5 0
2 years ago
77%<br> Calculate the area of this triangle.<br> 14 cm<br> 11 cmi<br> 18 cm
RideAnS [48]

Answer:

A = 99 cm²

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2}  bh ( b is the base and h the perpendicular height )

Here b = 18 and h = 11 , then

A = \frac{1}{2} × 18 × 11 = 9 × 11 = 99 cm²

4 0
2 years ago
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