Answer:
3√11
Step-by-step explanation:
You use the Pythagorean Therom, 18^2-15^2 give you 99. You find the square root of 99, you break it down into 9 and 11. Take the square root of 9, which is three, and you cant seperate 11. So thats how you get 3√11
This kind of decimal is called a terminating decimal, meaning it ends rather than repeating on forever like this one: 4.5555555555...... or the fraction 2/3 when you turn it into a decimal.
Answer:
![a=[2q^{2}r]](https://tex.z-dn.net/?f=a%3D%5B2q%5E%7B2%7Dr%5D)
![b=[3s^{2}t]](https://tex.z-dn.net/?f=b%3D%5B3s%5E%7B2%7Dt%5D)
Step-by-step explanation:
we have
we know that
![8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}](https://tex.z-dn.net/?f=8q%5E%7B6%7Dr%5E%7B3%7D%3D%282%5E%7B3%7D%29%28q%5E%7B2%7D%29%5E%7B3%7Dr%5E%7B3%7D%3D%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D)
![27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}](https://tex.z-dn.net/?f=27s%5E%7B6%7Dt%5E%7B3%7D%3D%283%5E%7B3%7D%29%28s%5E%7B2%7D%29%5E%7B3%7Dt%5E%7B3%7D%3D%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D)
therefore
substitute
![[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})](https://tex.z-dn.net/?f=%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D%20%2B%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D%3D%28%5B2q%5E%7B2%7Dr%5D%2B%5B3s%5E%7B2%7Dt%5D%29%28%5B2q%5E%7B2%7Dr%5D%5E%7B2%7D%20-%5B2q%5E%7B2%7Dr%5D%5B3s%5E%7B2%7Dt%5D%2B%5B3s%5E%7B2%7Dt%5D%5E%7B2%7D%29)
![[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])](https://tex.z-dn.net/?f=%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D%20%2B%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D%3D%28%5B2q%5E%7B2%7Dr%5D%2B%5B3s%5E%7B2%7Dt%5D%29%28%5B4q%5E%7B4%7Dr%5E%7B2%7D%5D%20-6%5Bq%5E%7B2%7Dr%5D%5Bs%5E%7B2%7Dt%5D%2B%5B9s%5E%7B4%7Dt%5E%7B2%7D%5D%29)
Answer:
They wore animal skins for clothing
Step-by-step explanation:
