Answer:
def find_max(num_1, num_2):
max_val = 0.0
if (num_1 > num_2): # if num1 is greater than num2,
max_val = num_1 # then num1 is the maxVal.
else: # Otherwise,
max_val = num_2 # num2 is the maxVal
return max_val
max_sum = 0.0
num_a = float(input())
num_b = float(input())
num_y = float(input())
num_z = float(input())
max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)
print('max_sum is:', max_sum)
Explanation:
I added the missing part. Also, you forgot the put parentheses. I highlighted all.
To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)
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Answer:
Option B 120
Explanation:
There are three variables,<em> ans, x </em>and <em>y</em> given in the code. In beginning, the variable. <em>ans,</em> holds value of 10. And variable <em>x</em> and <em>y</em> hold value of 65 and 55, respectively. Since the value held by x is bigger than one held by y, the if condition is met and the statement ans = x + y will run. The execution of this statement will total x with y -> 65 + 55 and the initial value of <em>ans is </em>overwritten by the addition result which is 120.
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