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MrRa [10]
3 years ago
8

Your organization has an Active Directory domain. One of the users, Bill, should not have read access to a folder named Accounti

ng. The Accounting folder is shared on a network server, on a partition formatted as NTFS. Which of the following statements best describes how to stop Bill from having read access to the folder without impacting any other users on the network?
A. Remove Bill from all domain groups that have access to the Accounting folder.
B. Deny read access to the Accounting folder for Bill through local access security.
C. Deny read access to the Accounting folder for any group that Bill is a member of.
D. Deny read access to the Accounting folder for Bill through shared access security.
Computers and Technology
1 answer:
Alborosie3 years ago
5 0

Answer: D. Deny read access to the Accounting folder for Bill through shared access security.

Explanation:

The statement that describes how to stop Bill from having read access to the folder without impacting any other users on the network is to deny read access to the Accounting folder for Bill through shared access security.

It should be noted that the local access security cannot be used in this case because the folder is shared from a network server that is within the active directory domain.

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When you use the bufferedreader class, you must import the ____ package into your program?
BigorU [14]
When you use the bufferedreader class, you must import the java.io package into your program.  It is<span> an API that comes with </span>Java<span> which is aimed at reading and writing data (input and output). ... For instance, read data from a file and write to a file or write a response back over the network. The </span>Java IO<span> API is located in the </span>Java IO<span> package ( </span>java.io<span> ).</span>
5 0
3 years ago
Suppose that the following elements are added in the specified order to an empty binary search tree: Kirk, Spock, Scotty, McCoy,
patriot [66]

Answer:

Pre-order: Kirk, Chekov, Khaaaan, Spock, Scotty, McCoy, Sulu, Uhuru

In-order: Chekov, Khaaaan, Kirk, McCoy, Scotty, Spock, Sulu, Uhuru

Post-order: Khaaaan, Chekov, McCoy, Scotty, Sulu, Uhuru, Spock, Kirk

Explanation:

The binary search tree is described in the diagram below.

The pre-order traversal of the binary tree gets the root, then the left node and right node. The in-order traversal picks the left node, the root node, and then the right node while the post-order traversal of the binary tree follows the left node, right node, and then the root node.

6 0
3 years ago
Write an algorithm that receives a number from the user (you can store the number in a variable called N). Then the algorithm sh
lbvjy [14]

Answer:

Algorithm:

1. Declare an integer variable N.

2. Read the value N from user.

3.While(N):

 3.1 find r=N%10;

 3.2 print r in new line.

 3.3 Update N as N=N/10.

4.end program.

Implementation in C++.

// header

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variable

int N;

cout<<"Enter an Integer:";

   cin>>N;

// find the digits of number

   while(N)

   {

       // last digit

       int r=N%10;

       // print last digit

       cout<<r<<endl;

       // update the number

       N=N/10;

}

return 0;

}

Output:

Enter an Integer:329                                        

9                                                          

2                                                          

3

7 0
3 years ago
Victoria has a .... of playing with her hair when she gets nervous​
IrinaK [193]

Answer:

Victoria has a tendency of playing with her hair when she gets nervous.

Explanation:

I believe this is what you are asking for.

:))))

6 0
3 years ago
The following method public String removeFromString(String old, String frag) removes all occurences of the string frag from the
Mashutka [201]

private static String removeFromString(String old, String frag)

{

int i = old.indexOf(frag);

while (i> -1) {

String rest = old.substring(i + frag.length());

System.out.println("rest = " + rest);

old = old.substring(0, i);

System.out.println("rest = " + old);

old = old + rest;

System.out.println("rest = " + old);

i = old.indexOf(frag);

System.out.println("i = "+ i);

}

return old;

}

Here the index of first occurrence is obtained outside the “while loop” and if this loop runs until index value is >-1. It extracts the rest of the characters other than “frag” from the index and all the characters for which the given set of characters are removed.

4 0
3 years ago
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