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3 years ago

9

What is the angle of DBC

1 answer:

Licemer1 [7]3 years ago

8 0

When added, these two angles are supplementary, meaning that their sum is 180. This means that we can do the following to find x, and eventually DBC:

3x+67+4x+50=180
Simplifies to:
7x+117=180
Then by the Subtraction Prop. of Equality:
7x=63
Then divide by 7 on both sides to get that x=9.

We then substitute 9 into angle DBC.
4(9)+50
=36+50
DBC=86

:)

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Solution:

Use Newton's Law of Cooling.

T = T_s + (T_0 - T_s)*e^(-kt)

where

T = temperature at any instant

T_s = temperature of surroundings

T_0 = original temperature

t = elapsed time

k = constant

Now, we need to find this constant. We are given that after one hour, the temperature drops to 13° C in a 7°C Environment.

T = 14, T_0 = 24, T_s = -15, t = 1, k = ?

T = T_s + (T_0 - T_s)*e^(-kt)

==> 14 = -15 + (24 - 7)*e^(-k)

==> 14 = 7 + 17*e^(-k)

==> 7 = 17*e^(-k)

==> 7/13 = e^(-k)

==> -k = ln(7/17)

==> k = -ln(7/17) ≈ 0.774

Now,

Let's calculate temperatures!

T = ?, T_0 = 24, T_s = -15, k = 0.773, t = 3

T = T_s + (T_0 - T_s)*e^(-kt)

==> T = -15 + (24 –(-15))*e^[ -(0.774)(2) ]

==> T = -15 + 39*e^(-1.548)

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3 years ago

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The centroid of a triangle divides the median of the triangle into 1 : 2

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Because point T is the centroid, then we have the following ratio

$\mathbf{TQ : FT =1 : 2}$

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Substitute 12 for FT in the above ratio

$\mathbf{TQ : 12 =1 : 2}$

Express as fraction

$\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}$

Multiply both sides by 12

$\mathbf{TQ =\frac{1 }{ 2} \times 12}$

This gives

$\mathbf{TQ =\frac{1 2}{ 2}}$

Divide 12 by 2

$\mathbf{TQ =6}$

The measure of FQ is calculated using:

$\mathbf{FQ = FT + TQ}$

Substitute 12 for FT, and 6 for TQ

$\mathbf{FQ = 12 + 6}$

Add 12 and 6

$\mathbf{FQ = 18}$

Hence, the measure of FQ is 18, while the measure of TQ is 6

Read more about centroids at:

brainly.com/question/11891965

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