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3 years ago

ABC is a triangle. Work out the size of the angle marked p.

Mathematics

1 answer:

mario62 [17]3 years ago

5 0

Answer:

p= angle180_(50+70)

p=180_120

angle p=60

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louine bought a computer for 180$ and paid 10.80$ what percent of the cost is the sales tax? (Please help and explain)

leonid [27]

6%
to find the percentage you divide 10.80$ by 180$ and get 0.06
0.06 is 6% in decimal form
therefore there was 6% sales tax (sales tax is usually 6-8% so this makes sense anyway)

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3 years ago

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Dafna11 [192]

Answer:

An expression is a number, a variable, or a combination of numbers and variables and operation symbols. An equation is made up of two expressions connected by an equal sign.

Step-by-step explanation:

Hopes this help.

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3 years ago

What number could replace x to make a true statement?

Rudik [331]

Answer:

5 i think

Step-by-step explanation:

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4 years ago

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In the rectangle below, AC has a length of 28 units. What is the length of DE?

Amiraneli [1.4K]

Answer:

D. 14 units

Step-by-step explanation:

it is a rectangle.

that means both diagonals are equally long.

E is in the middle of of diagonals.

so, since the whole diagonal (AC = DB) is 28 units long, one half of such a diagonal (AE = EC = DE = EB) is then

28/2 = 14 units long.

4 0

3 years ago

A company takes out an insurance policy to cover accidents that occur at its manufacturing plant. The probability that one or mo

yKpoI14uk [10]

Answer:

0.289792.

Step-by-step explanation:

If we define a month with one or more accident as "success"; and

A month with no accident as "failure" .

P(one or more accidents will occur during any given month)=0.60.
P(no accident will occur during any given month)=1-0.60=0.40

We want to calculate the probability that there will be at least four months in which no accidents occur before the fourth month in which at least one accident occurs.

in this case, let k=number of failures before the fourth success

Therefore, $k\geq 4$

k follows a negative binomial distribution.

Therefore, the probability is:

$P(k\geq 4)=1-P(k\leq 3)\\=1-\sum_{k=0}^{3}\left(\begin{array}{ccc}3+k\\k\end{array}\right)(0.60)^4(0.40)^k\\=1-(0.60)^4 \left[\left(\begin{array}{ccc}3\\0\end{array}\right)(0.40)^0+\left(\begin{array}{ccc}4\\1\end{array}\right)(0.40)^1+\left(\begin{array}{ccc}5\\2\end{array}\right)(0.40)^2+\left(\begin{array}{ccc}6\\3\end{array}\right)(0.40)^3\right]\\=1-(0.60)^4 \left[ 1+1.6+1.6+1.28\right]\\=1-(0.60)^4[5.48]\\=0.289792$

The required probability is 0.289792.

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3 years ago