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Setler79 [48]
3 years ago
8

Circle F is inscribed with quadrilateral E D C B. Point A is on the circle between points E and B. Angle D E B is 70 degrees and

angle D B C is 80 degrees. The measure of arc D C is 88 degrees. What is the measure of Arc E A B in circle F?
Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
5 0
A and e can’t connect cause they are not the same letter
Veronika [31]3 years ago
3 0

Answer:

c

Step-by-step explanation:

c

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I'll give brainlest if u can answer this question <br><br><br>1+1=?
yKpoI14uk [10]

Answer:

11

Step-by-step explanation:

LOL

3 0
3 years ago
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Find the square root of 291600 by prime factorization​
yarga [219]

Answer:

540

Step-by-step explanation:

I honestly put it in my calculator and squared it,

   291600

  /           \

540         540

you have a pair, you don't have to do anything else, and you're done

3 0
4 years ago
Will give most points!!!!(06.02)Jordan plotted the graph below to show the relationship between the temperature of his city and
Lubov Fominskaja [6]

Answer:

Part A: Linear relationship

Part B: Using the dividing method

Slope = -3.325

y-intercept is (0, 88.5)

Step-by-step explanation:

Part A

The is an approximately linear relationship between the temperature of his city and the number of chocolate sold

Part B

The line of best fit can be drawn by

1) Plot the data points on the graph

2) Divide the number of data points into two with a vertical dotted line

3) Mark the center of the data on each side of the dividing central line with an a or x

4) Draw a straight line through the x marks that extends to the plot edges

5) The straight line drawn is the line of best fit

The approximate slope is found from points (0, 90) and (20, 20) using the formula for gradient, m, such that we have;

m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where:

y₁ = 88

x₁ = 0

y₂ = 22

x₂ = 20

Therefore;

The \ slope, \ m =\dfrac{22-88.5}{20-0} = \dfrac{-66.5}{20} =-3.325

From the graph, the y-intercept is approximately (0, 88.5) while the x intercept is approximately (26.5, 0)

8 0
3 years ago
A noise level of a lawn tractor is approximately
Natali5045456 [20]

Answer:

Step-by-step explanation:

Since the noise level of a lawn tractor is approximately

normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = the noise level

u = mean noise level

s = standard deviation

From the information given,

u = 100 decibels

s = 3 decibels.

We want to find the probability that a randomly selected lawn tractor will generate a noise level of

more than 105 decibels. It is expressed as

P(x > 105) = 1 - P(x ≤ 105)

For x = 105,

z = (105 - 100)/3 = 1.67

Looking at the normal distribution table, the probability corresponding to the z score is 0.9525

P(x > 105) = 1 - 0.9525 = 0.0475

3 0
3 years ago
​write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)
Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

log_{4 }6ab

This can be written as

log_{4 }6 \times a \times b

From one of the rules of logarithm, we have that

log_{x }yz= log_{x }y + log_{x }z

Thus,

log_{4 }6 \times a \times b  becomes

log_{4 }6 + log_{4 }a + log_{4 }b

This can be further simplified into

log_{4 }3 \times 2 + log_{4 }a + log_{4 }b

log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b

If desired, this can be further simplified into

log_{4 }3 + log_{2^{2}  }2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b

\frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

8 0
2 years ago
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