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pav-90 [236]
4 years ago
6

an airplane has 64 rows of seats with 3 seats in the left section 4 seats in the middle middle section and 2 seats in the right

how many passengers can the plane hold
Mathematics
1 answer:
NemiM [27]4 years ago
7 0
Go 3+4+2 to determine for 1 row and then multiply that by 64 so 576
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Which algebraic expression represents the phrase “the quotient of negative eight and the sum of a number and three”?
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3 years ago
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Tasha plans to tile the floor in her room with square tiles that are 1/4 foot long. Will she use more or fewer tiles if she is o
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She will need less tiles because the common dinominator of 4 and 3 is 12.
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do as you see 1/3 is greater than 1/4 therefore she will need less tiles
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3 years ago
Which steps should be used to graph the equation y – 4 = y minus 4 equals StartFraction one-third EndFraction left-parenthesis x
dalvyx [7]

Answer:

The steps are are explained below.

Step-by-step explanation:

Given:

The equation of the line is given as:

y-4=\frac{1}{3}(x+2)

The above equation is in point-slope form y-y_1=m(x-x_1).

Therefore, on comparing, we get

x_1=-2,y_1=4,m=\frac{1}{3}

So, the slope is one-third and point is (-2,4).

Now, following are steps for plotting the graph:

i. Plot the point (-2,4).

ii. Since the slope is one-third, it means we need to move 3 units to right from the point (-2,4) and then 1 unit up. So, after translating 3 units right and 1 unit up we mark the second point which is (-2+3,4+1)\rightarrow )(1,5).

iii. Draw a line passing through the points (-2,4) and (1,5) to get the graph of the line

Thus, the graph is drawn below.

8 0
3 years ago
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Only 4 and 5 help help
stich3 [128]
Pythagorean theorem is a^2 + b^2 =c^2 4)8.9
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Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var
Natalija [7]

Answer:

\displaystyle y=5+\frac{x}{10}

\displaystyle y=10+\frac{(x-75)}{20}

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

y=f(x)=f(a)+f'(a)(x-a)

Let's find the linearization for the function

y=\sqrt{25+x}

at (0,5) and (75,10)

Computing f'(x)

\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}

At x=0:

\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}

We find f(0)

f(0)=\sqrt{25+0}=5

Thus the linearization is

\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x

\displaystyle y=5+\frac{x}{10}

Now at x=75:

\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}

We find f(75)

f(75)=\sqrt{25+75}=10

Thus the linearization is

\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)

\displaystyle y=10+\frac{(x-75)}{20}

5 0
3 years ago
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