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3 years ago

Find the area of the triangle

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

7 0

The area of a triangle is equal to bh/2.
The base here is 8 and the height is 3.
8*3=24
24/2=12
The answer is B, 12 yd^2

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sveta [45]

1. and 2.
$8 \frac{5}{12} \\ 13 \frac{2}{7}$

5 0

4 years ago

A box contains 6 wooden, straight sticks of the following lengths (in inches): 2, 3, 5, 7, 11, and 13. Three sticks are drawn at

Vikentia [17]

Answer:

$\dfrac{1}{4}$

Step-by-step explanation:

given,

straight stick of length = 2, 3, 5, 7, 11, and 13.

For a triangle to form third side of the sum of the two side of the triangle should be greater than third.

so the possibility of triangle formed

5,11,13

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3,11,13

7,5,11

5,3,7

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3 years ago

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Blizzard [7]

Answer:

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8 0

3 years ago

Explain your answer !! Have a nice day Will give braisnlt

SashulF [63]

Answer:

The equations are:

$4H + 3P = 13.75$

$2H + 5P = 11.25$

$Hotdog = 2.50$

$Pretzel = 1.25$

Step-by-step explanation:

Let:

$H = hot\ dog$

$P =Pretzel$

For Tina:

$4H + 3P = 13.75$

For Doug:

$2H + 5P = 11.25$

Solving for the price of both items:

We have:

$4H + 3P = 13.75$ --- (1)

$2H + 5P = 11.25$ --- (2)

Multiply (2) by 2

2 * ( $2H + 5P = 11.25$ )

-------------------

$4H + 10P = 22.50$ --- (3)

Subtract (3) from (1)

$4H + 3P = 13.75$

$4H + 10P = 22.50$

----------------------

$4H - 4H + 3P - 10P = 13.75 - 22.50$

$3P - 10P = 13.75 - 22.50$

$-7P = -8.75$

Solve for P

$P = \frac{-8.75}{-7}$

$P = 1.25$

Substitute 1.25 for P in (2)

$2H + 5P = 11.25$

$2H + 5 * 1.25 = 11.25$

$2H + 6.25 = 11.25$

Collect Like Terms

$2H = 11.25-6.25$

$2H = 5$

Solve for H

$H = \frac{5}{2}$

$H = 2.50$

5 0

3 years ago

An arborist wants to prune an oak tree that has grown too tall. The arborist takes a 15-foot ladder and places it on a horizonta

SCORPION-xisa [38]

See the attached picture to better understand the problem

we know that
in the right triangle ABC
cos 70=adjacent side angle 70/hypotenuse
adjacent side angle 70=BC----> distance between the ladder and the tree trunk
hypotenuse=AC------> 15 ft

cos 70=BC/AC-------> solve for BC
BC=AC*cos 70------> BC=15*cos 70-----> BC=5.13 ft

the answer is
the distance between the ladder and the tree is 5.13 ft

8 0

3 years ago