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amm1812
3 years ago
10

Find the area of the triangle

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0
The area of a triangle is equal to bh/2.
The base here is 8 and the height is 3.
8*3=24
24/2=12
The answer is B, 12 yd^2
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ikadub [295]

Answer:

0

Step-by-step explanation:

Slope = Δy/Δx

Slope = 10-10/4-1

Slope = 0/3

Slope = 0

It is a Horizontal Line

-Chetan K

6 0
2 years ago
Given: AB || DE , AD bisects BE.<br> Prove: ABC = DEC using the ASA postulate.
Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

\triangle ABC and \triangle DEC.

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.

i.e. AB || ED and \angle B and \angle E are alternate angles \Rightarrow \angle B = \angle E.

2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

\Rightarrow \angle ACB = \angle DCE

Also, it is given that <em>AD bisects BE</em>.

i.e. EC = CB

1. \angle B = \angle E

2. EC = CB

3. \angle ACB = \angle DCE

So, we can in see that in \triangle ABC and \triangle DEC, two angles are equal and side between them is also equal to each other.

Hence, proved that \triangle ABC \cong \triangle DEC.

8 0
3 years ago
a boat builer wamts to make a modle of a schooner, a type of sailboatwith at least two masts. the schooner is 34 meters in lengt
BlackZzzverrR [31]
First you should set up fractions equal to each other to see the size ratio

8/34 = x/1.2

As to make comparable fractions. Then you would cross multiply in order to get
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6 0
3 years ago
Which of the following mixed numbers has a value between 6 and 7?
ser-zykov [4K]
I feel like it’s B but I’m not sure
7 0
2 years ago
What is a simplified expression for the perimeter of the polygon?
serious [3.7K]

Answer:

D. 5x^2 + 2y^2 + 12x + 5y

Step-by-step explanation:

6x + 2y + y^2 + 6x + 2y + y^2 + 4x^2 + x^2 + y

6x + 6x = 12x

12x + 2y + y^2 + 2y  + y^2 + 4x^2 + x^2 + y

2y + 2y + y = 5y

12x + 5y + y^2 + y^2 + 4x^2 + x^2

y^2 + y^2 = 2y^2

2y^2 + 4x^2 + x^2 + 12x + 5y

4x^2 + x^2 = 5x^2

2y^2 + 5x^2  + 12x + 5y

5x^2 + 2y^2 + 12x + 5y

7 0
3 years ago
Read 2 more answers
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