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olchik [2.2K]
2 years ago
8

Find the area and the circumference of a circle with diameter 8 ft.

Mathematics
1 answer:
masha68 [24]2 years ago
5 0

Answer:

a. Area of circle = 50.24 ft².

b. Circumference of circle = 25.12 ft.  

Step-by-step explanation:

Given the following data;

Diameter = 8ft

Pie, π = 3.14

Radius, r = diameter/2 = 8/2 = 4ft

a. To find the area of the circle;

Area of circle = πr²

Substituting into the equation, we have;

Area of circle = 3.14*(4)²

Area of circle = 3.14*16

<em>Area of circle = 50.24 ft²</em>

b. To find the circumference of the circle;

Circumference of a circle = 2πr

Substituting into the equation, we have;

Circumference of circle = 2*3.14*4

<em>Circumference of circle = 25.12 ft. </em>

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Let n represent the unknown number.  

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              n = 10.4 / 14.4%
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Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

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3 years ago
You brought 1.5 dozen bagels to school. A dozen bagels cost $5.98. You used a coupon that took $1.00 off of the total. How much
shusha [124]

Answer:   (7.97)

Step-by-step explanation:

1 dozen = 5.98

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5.98+2.99=8.79 8.79- the 1.00 is (7.97)

hope this helps!

3 0
3 years ago
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