Answer:
-5
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
45−(5+8y−3(y+3))=−3(3y−5)−(5(y−1)−2y+6)
45+−1(5+8y−3(y+3))=−3(3y−5)+−1(5(y−1)−2y+6)(Distribute the Negative Sign)
45+(−1)(5)+−1(8y)+−1(−3(y+3))=−3(3y−5)+−1(5(y−1))+−1(−2y)+(−1)(6)
45+−5+−8y+3y+9=−3(3y−5)+−5y+5+2y+−6
45+−5+−8y+3y+9=(−3)(3y)+(−3)(−5)+−5y+5+2y+−6(Distribute)
45+−5+−8y+3y+9=−9y+15+−5y+5+2y+−6
(−8y+3y)+(45+−5+9)=(−9y+−5y+2y)+(15+5+−6)(Combine Like Terms)
−5y+49=−12y+14
−5y+49=−12y+14
Step 2: Add 12y to both sides.
−5y+49+12y=−12y+14+12y
7y+49=14
Step 3: Subtract 49 from both sides.
7y+49−49=14−49
7y=−35
Step 4: Divide both sides by 7.
7y
7
=
−35
7
y=−5
Steps:
7w - 2 + w = 2(3w - 1)
6w - 2 = 6w - 2
Because both sides of the equation are equal, w = an infinite amount of solutions.
Have a great day!
Answer:
Step-by-step explanation:
Let the age be xy or 10x + y.
Reverse the two digits of my age, divide by three, add 20, and the result is my age, convert this to equation:
- (10y + x)/3 + 20 = 10x + y
- (10y + x)/3 = 10x + y - 20
- 10y + x = 3(10x + y - 20)
- 10y + x = 30x + 3y - 60
- 30x - x + 3y - 10y = 60
- 29x - 7y = 60
We should consider both x and y are between 1 and 9 since both the age and its reverse are 2-digit numbers.
Possible options for x are:
- 29x ≥ 7*1 + 60 = 67 ⇒ x > 2, at minimum value of y,
and
- 29x ≤ 7*9 + 60 = 123 ⇒ x < 5, at maximum value of y.
So x can be 3 or 4.
<h3>If x = 3</h3>
- 29*3 - 7y = 60
- 87 - 7y = 60
- 7y = 27
- y = 27/7, discarded as fraction.
<h3>If x = 4</h3>
- 29*4 - 7y = 60
- 116 - 7y = 60
- 7y = 56
- y = 8
So the age is 48.
Eight hundred seventy six thousand five hundred forty three.
Answer:
Only one extreme value of f(x) is possible.
Step-by-step explanation:
We are given the quadratic function of independent variable x which is f(x) = x² - 7x - 6 ......(1)
Now. the condition for extreme values of f(x) is 
Hence, differentiating both sides of equation (1) with respect to x, we get
= 0
⇒ x = 3.5.
So there is only one value of x for which f(x) has extreme value which is x = 3.5.
Therefore, only one extreme value of the given function is possible. (Answer)