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zalisa [80]
2 years ago
6

If f(x)=-5 find the value of x​

Mathematics
1 answer:
Greeley [361]2 years ago
5 0

f(x) is a fancy way to say y

The equation says y=05, so x is ungiven based on what you have given us. Please check if there was more information written as usually its written as

Example: f(x)=3x+5

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Give it in the function f(x) equals 4X describe the transformation to the graph for the following f(x+1)
Andrew [12]

Answer:

  f(x) is shifted 1 unit left

Step-by-step explanation:

The transformation accomplished by f(x-h) is to shift the graph of the function f(x) to the right by "h" units. Here, the value of h is -1, so the graph is shifted left by 1 unit.

8 0
3 years ago
1 . What is the distance between the two points. (0,5 1,3), (-0,4, -1,3) ?
Studentka2010 [4]

Answer:

Step-by-step explanation:

x1 = 0.5 x2 = -0.4 y1 = 1.3 y2 = -1.3

\sqrt{(x2 - x1)^{2}+(y2 - y1)^{2}

\sqrt{(-0.4 - 0.5)^{2}+(-1.3 - 1.3)^{2}

=2.75

6 0
3 years ago
HELP ME PLZZZ!!!! URGENT!!!​
finlep [7]

Answer:

Step-by-step explanation:

Given equation is,

x² + (p + 1)x = 5 - 2p

x² + (p + 1)x - (5 - 2p) = 0

x² + (p + 1)x + (2p - 5) = 0

Properties for the roots of a quadratic equation,

1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]

2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]

3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].

Discriminant of the given equation = (p+1)^2-4(1)(2p-5)

For real roots,

(p+1)^2-4(1)(2p-5)>0

p² + 2p + 1 - 8p + 20 > 0

p² - 6p + 21 > 0

For all real values of 'p', given equation will be greater than zero.

5 0
3 years ago
Write -7 2/3 as an improper fraction. please
SIZIF [17.4K]
- 23/3 is your answer
3 0
3 years ago
Read 2 more answers
PLEASE HELP ME.
Juli2301 [7.4K]

Answer:

its a counterclockwise rotation of 90° about the origin.

Step-by-step explanation:

3 0
3 years ago
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