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kobusy [5.1K]
3 years ago
15

Write word problems that represent each way you can use a remainder in a division problem.include solutions.

Mathematics
2 answers:
ratelena [41]3 years ago
5 0
Jack has 60 toys. He wants to store all of them in boxes. Each box can hold 9 toys. How many boxes does Jack need?

The key word is 'all'. There is a remainder because 9 doesn't go into 60 evenly. He wants to store all the toys, so he needs an extra box for the leftover toys.
jasenka [17]3 years ago
4 0
4 divided by 18 = 4 multiply by 4= 16 =2 then add and bring down 0 =20 so 4 times 5 = 20 so = 4.5

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What greatest three digit number whose hundreds is two less than its ones digit
kodGreya [7K]

Answer:

799

Step-by-step explanation:

Let x = the hundreds digit

Let y = the ones digit

x = y-2

We want to maximize x and y.  The both have to be single digit numbers

Rewriting this

x+2 =y

The largest x can be is 7 if y is a single digit

x is 7 and y is 9

We can pick the tens digit.  Make it as big as possible to make out number as large as possible

799

4 0
3 years ago
(-3,600,000,000)x(0.00000824)
Nadusha1986 [10]
-29664 is the correct answer. This mostly deals with the zeros and crossing them off
8 0
3 years ago
Due right now help ill mark you brainly if its correct
AleksandrR [38]

Answer:

all but 1/6

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Solve<br> 2x − 4y = 2<br> y = 4
liberstina [14]

Point Form:

( 9 , 4 )

Equation Form:

x = 9 ,  y= 4

7 0
3 years ago
Read 2 more answers
Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir
kati45 [8]
\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad &#10;radius=\stackrel{}{ r}\\\\&#10;-------------------------------\\\\&#10;(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~&#10;\begin{cases}&#10;\stackrel{center}{(-1,0)}\\&#10;\stackrel{radius}{6}&#10;\end{cases}

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}&#10;\\\\\\&#10;d=\sqrt{0+1}\implies d=1

well, the distance from the center to A is 1, namely is "inside the circle".

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}&#10;\\\\\\&#10;d=\sqrt{0+36}\implies d=6

notice, the distance to B is exactly 6, and you know what that means.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})&#10;\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}&#10;\\\\\\&#10;d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.
3 0
3 years ago
Read 2 more answers
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