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3 years ago

Write word problems that represent each way you can use a remainder in a division problem.include solutions.

2 answers:

5 0

Jack has 60 toys. He wants to store all of them in boxes. Each box can hold 9 toys. How many boxes does Jack need?

The key word is 'all'. There is a remainder because 9 doesn't go into 60 evenly. He wants to store all the toys, so he needs an extra box for the leftover toys.

jasenka [17]3 years ago

4 0

4 divided by 18 = 4 multiply by 4= 16 =2 then add and bring down 0 =20 so 4 times 5 = 20 so = 4.5

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What greatest three digit number whose hundreds is two less than its ones digit

kodGreya [7K]

Answer:

799

Step-by-step explanation:

Let x = the hundreds digit

Let y = the ones digit

x = y-2

We want to maximize x and y. The both have to be single digit numbers

Rewriting this

x+2 =y

The largest x can be is 7 if y is a single digit

x is 7 and y is 9

We can pick the tens digit. Make it as big as possible to make out number as large as possible

799

4 0

3 years ago

(-3,600,000,000)x(0.00000824)

Nadusha1986 [10]

-29664 is the correct answer. This mostly deals with the zeros and crossing them off

8 0

3 years ago

Due right now help ill mark you brainly if its correct

AleksandrR [38]

Answer:

all but 1/6

Step-by-step explanation:

7 0

2 years ago

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Solve<br> 2x − 4y = 2<br> y = 4

liberstina [14]

Point Form:

( 9 , 4 )

Equation Form:

x = 9 , y= 4

7 0

3 years ago

Read 2 more answers

Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir

kati45 [8]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}$

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1$

well, the distance from the center to A is 1, namely is "inside the circle".

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6$

notice, the distance to B is exactly 6, and you know what that means.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398$

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

3 0

3 years ago

Read 2 more answers