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kodGreya [7K]
3 years ago
6

Dtermine whether the following value is a continuous random​ variable, discrete random​ variable, or not a random variable.

Mathematics
1 answer:
Vikki [24]3 years ago
8 0

Answer:

a) Discrete random variable

b) Not a random variable

c) Discrete random variable

d) Continuous random variable

e) Discrete random variable

f) Continuous random variable

Step-by-step explanation:

a) This is discrete because we can quantify it and it can not take a decimal number and has true zero. That is, zero means absence.

b) This is not a random variable because hair color is quality, thus it cannot be quantify.

c) This is discrete because we can quantify it and it can not take a decimal number and has true zero. That is, zero means absence.

d) This is continuous random variable because we can quantify it, it can take decimal number and has no true zero. For instance, 0 degree Celsius does not implies absence of temperature. Or that we say someone is a dwarf does not implies he/she has no height even though the measure scale may read zero.

e) This is discrete because we can quantify it and it can not take a decimal number and has true zero. That is, zero means absence.

f) This is continuous random variable because we can quantify it, it can take decimal number and has no true zero. For instance, 00:00 GMT does not implies absence of time.

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For the first question, he would raise $38.

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It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
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Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

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  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

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  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

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2 years ago
The reasons as well as the answer
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Answer:

x = 46, y = 67

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Answer:

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