Answer:
Step-by-step explanation:
What is the slope slope of a line that is perpendicular to the line represented by the equation y-5x=5 ?
2 answers:
Answer:
Step-by-step explanation:
We know that the general intercept form of equation of line is given by :-
, where m is the slope of the line.
The given equation of line :
Subtract 5x both sides, we get
On comparing the equation to the general intercept form of equation of line , we get
Slope =5
Since the product of slopes of perpendicular lines is -1.
Then the slope of line that is perpendicular to the given equation will be :-
You might be interested in
Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
= Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).
