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bogdanovich [222]
3 years ago
6

Please help me with this question I will mark you as the best answer if correct

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

Line : y = ax + b, passes (0, 3) and (2, -3)

=> b = 3

=> 2a + b = -3

=> a = -6/2 = -3

=> Slope a = -3

=> Option D is correct

Hope this helps!

:)

vlabodo [156]3 years ago
3 0

Answer:

D is the answer

Step-by-step explanation:

Slope = rise / run

Slope = y2-y1 / x2-x1

Where coordinates are

(0,3),(2,-3)

So x1=0,y1=3 , x2=2 , y2= -3

Slope= -3-3/ 2-0

Slope = -6/2

Slope = -3

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timama [110]

Use the change-of-basis identity,

\log_x(y) = \dfrac{\ln(y)}{\ln(x)}

to write

xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}

Use the product-to-sum identity,

\log_x(yz) = \log_x(y) + \log_x(z)

to write

xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}

Redistribute the factors on the left side as

xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}

and simplify to

xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)

Now expand the right side:

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}

Simplify and rewrite using the logarithm properties mentioned earlier.

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1

xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}

xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}

xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)

\implies \boxed{xyz = x + y + z + 2}

(C)

6 0
2 years ago
A large tank is partially filled with 100 gallons of fluid in which 20 pounds of salt is dissolved. Brine containing 1 2 pound o
sertanlavr [38]

Answer:

Step-by-step explanation:

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Given that the solution is pumped at a slower rate of 4gal/min

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Integrating the linear differential equation; we have::

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multiplying above integrating factor fields; we have:

(50 +t)^2 \dfrac{dA}{dt} + 2 (50 + t)A = 3 (50 +t)^2

\dfrac{d}{dt}\bigg [ (50 +t)^2 A \bigg ] = 3 (50 +t)^2

(50 + t)^2 A = (50 + t)^3+c

A = (50 + t) + c(50 + t)²

Using the given conditions:

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c = -30 × 2500

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The no. of pounds of salt in the tank after 35 minutes is:

A(35) = (50 + 35) - 75000(50 + 35)⁻²

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C ($56) - ($2) - ($3)

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4 years ago
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Bumek [7]

Answer:

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Step-by-step explanation:

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3 years ago
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