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nirvana33 [79]
3 years ago
5

All real numbers greater thab or equal to 67

Mathematics
1 answer:
sineoko [7]3 years ago
5 0
An equation for that would be.

x => 67
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Divide. Write your answer as a fraction in simplest form. − 7 1/0÷2/5=
forsale [732]

Answer:

-  \frac{71}{4}

Step-by-step explanation:

- 7 \frac{1}{10}   \div   \frac{2}{5}

=   - \frac{71}{10}  \times  \frac{5}{2}

=  -  \frac{71}{2}  \times  \frac{1}{2}

=  -  \frac{71}{4}

4 0
3 years ago
Rick charges $50 plus $40 an hour to fix cars. Let x be the number of hours that he works and y be the overall cost that he char
Serjik [45]
Y= 40x+ 50 (i need 20 characters to post this so ignore)
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3 years ago
On Monday Sarah had homework in 7∕10 of her classes, Tuesday 3∕5 , Wednesday 9∕11 , and Thursday 1∕2 . Which day did she have th
Valentin [98]
It is Wednesday as it has the highest fraction of homework i.e
Monday has 0.7 of homework for her classes
Tuesday has 0.6
Wednesday has 0.81
Thursday has 0.5.
Therefore it has to be Wednesday.
Hope this helps :).

3 0
2 years ago
Write this ratio in simplest form: 72:9​
elena55 [62]

Answer:

12

Step-by-step explanation:12x9

3 0
2 years ago
Read 2 more answers
McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine
jonny [76]

Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

The pooled variance t-Test would have been determined if the population variance are the same.

S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}

S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}

S_p^2 = 7.14

The t-test statistics can be computed as:

t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}

t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}

t= \dfrac{3}{1.336}

t = 2.2450

Degree of freedom df = (n_1 -1) + ( n_2 +1 )

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

t _{critical} = 1.760

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject H_o and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

r^2 = \dfrac{5.040025}{5.040025+ 14}

r^2 = 0.2647

7 0
3 years ago
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