Express it in a+bi form

Mathematics

1 answer:

bulgar [2K]3 years ago

7 0

((1+4i)/i) +(1+i)/(2+5i)
(((1+4i)*(2+5i)) +((1+i)*i))/(i*(2+5i))
((2 + 8i + 5i +20i²) + (1i + i²) )/ (2i + 5i²)
((2 + 13i -20) + (1i -1))/(2i - 5) where i² = -1
((14i - 19) +0)/2i - 5
(14i -19)/(2i - 5)

You might be interested in

Determine the x-intercept and the y-intercept for the graph of this equation: 2x - 3y + 36 = 0

natali 33 [55]

QUESTION:- DETERMINE THE X-INTERCEPT AND THE Y-INTERCEPT FOR THE GRAPH OF THE EQUATION.

EQUATION:- 2x - 3y + 36 = 0

STANDARD EQUATION:- y=mx+c

where

m-> slope.
c-> Y-INTERCEPT
x&y are the coordinates.

SO GIVEN EQUATION:- 2x - 3y + 36 = 0

WE CAN SOLVE THIS TO CHANGE IN FORMAT OF STANDARD EQUATION

$2x - 3y + 36 = 0 \\ 2x + 36 =3y \\ y = \frac{2}{3} x + \frac{36}{3} \\ y = \frac{2}{3} x + \frac{ \cancel{36}^{ \: \: 12} }{ \cancel3} \\ y = \frac{2}{3} x + 12 \\$

SO :-

$m = \frac{2}{3} \\ y - intercept = 12 \: ans$

$slope = \frac{y2 - y1}{x2 - x1} \\ \frac{2}{3} = \frac{0 - 12}{x - 0} \\ 2x = ( - 12) \times 3 \\ x = \frac{ - \cancel{12}^{ \: \: 6} \times 3 }{ \cancel{2}} \\ x = - 18 \: \: ans$