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rjkz [21]
3 years ago
9

A wildfire is spreading at an alarming rate. The wildfire begins at a size of 8 square feet. It then doubles its width every x h

ours, and doubles its length every y hours. After a period of time, the wildfire covers 14,000 square feet.
Which equation correctly represents the area of the wildfire in terms of x and y?


A. 14,000 = 16^xy

B. 14,000 = 16xy

C. 14,000 = 8 ⋅ 2^x+y

D. 14,000 = 8 ∗ 2^xy
Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

D.

14000=8\times 2^{x+y}

Step-by-step explanation:

The wildfire begins at a size of 8 square feet

It means that initial area =8

It then doubles its width every x hours,

and doubles its length every y hours

so, we can set up equation

A(x,y)=8(2)^x\times (2)^y

now, we can simplify it

A(x,y)=8(2)^{x+y}

we are given

After a period of time, the wildfire covers 14,000 square feet

so, we can set A(x,y)=14000

we get

14000=8(2)^{x+y}

14000=8\times 2^{x+y}

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Answer:

  48

Step-by-step explanation:

The ratio of professors to lecturers is ...

  P : L = 6 : 11

Then the ratio of professors to total faculty is ...

  P : (P+L) = 6 : (6+11) = 6 : 17

That is, professors make up 6/17 of the total faculty. Their number is ...

  P = (6/17)·136 = 48

The Community College employs 48 professors.

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3 years ago
There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin
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Simplify the ratio:<br><br> 15 m: 5000 mm : 10 m
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Step-by-step explanation:

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3 years ago
Can somebody help me with this please
Hitman42 [59]
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3 years ago
Read 2 more answers
Select ALL the correct answers.
IgorC [24]

Answer:

A. 4(x - 4) + 2(3x² + 3x - 20)

C. (11x² + 7x - 55)-(5x² - 3x + 1)

F. (3x² + 5x - 28) + (3x² + 5x - 28)

Step-by-step explanation:

Given:

(3x-7)(2x+8)

= 6x² + 24x - 14x - 56

=6x² + 10x - 56

A. 4(x - 4) + 2(3x² + 3x - 20)

= 4x - 16 + 6x² + 6x - 40

= 6x² + 10x - 56

B. (3x² + 5x - 28) - (2x² + 4x + 28)

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= x² + x - 56

C. (11x² + 7x - 55)-(5x² - 3x + 1)

= 11x² + 7x - 55 - 5x² + 3x - 1

= 6x² + 10x - 56

D. 4(x - 4) - 2(3x² + 3x - 20)

= 4x - 16 - 6x² - 6x + 40

= - 6x² - 2x + 24

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= 11x² + 7x - 55 - 5x² + 3x - 2

= 11x² - 5x² + 7x + 3x - 55 - 2

= 6x² + 10x - 57

F. (3x² + 5x - 28) + (3x² + 5x - 28)

= 3x² + 5x - 28 + 3x² + 5x - 28

= 6x² + 10x - 56

7 0
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