Question

1. In a game, if you roll a 2 or a 3 on a 6-sided number cube, you lose a turn. NOTE: This is just using one number cube.

Answer 1

Answer:

1/3

Step-by-step explanation:

On a 6-sided number cube, the probability that you roll a 2 is 1/6,

(Remember that the probability equals: Number of positive outcomes/ number of possible outcomes) So you have 1 positive outcome (to roll a 2) among 6 possible outcomes.

This same thinking applies for the case of rolling a 3 and the probability is 1/6.

Now you want to roll either a 2 or 3. In probability, when we get an "or" this means that we have to sum up our probabilities.

Thus, the P(2 or 3) = $P(2)+P(3)= \frac{1}{6}+ \frac{1}{6} =\frac{2}{6}=\frac{1}{3}$

Thus the probability of rolling a 2 or 3 is 1/3