The given function is greater than or equal to 0 for the interval given as follows:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
<h3>When a function is positive and when it is negative?</h3>
- A function is positive when it is above the x-axis.
- A function is negative when it is below the x-axis.
For this problem, with a closed interval, we have that the function is above for:
x ≤ -3, -1 ≤ x ≤ 0, x ≥ 2.
Hence the interval notation is:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
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This is the concept of algebra, given that the formula for the surface area of the prism is modeled by the expression SA=2s²+4sh , the surface area of the prism when s=3 and h=5 will be found by substituting the values in our expression as follows;
SA=2(3)²+4×3×5
SA=2(9)+60
SA=18+60
SA=78 sq. units
The answer is 78 sq. units
In quadrant I, when sin angle is 1/2, cos angle is (sqrt3)/2