3 years ago

Did i get them right?

Mathematics

1 answer:

iogann1982 [59]3 years ago

3 0

Yes u did in fact get them right

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Need help please I’m begging yeah.

Simora [160]

Answer: The answer is B.

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3 years ago

motikmotik

Answer:

1st one is yes

Step-by-step explanation:

the other two im not sure about

4 0

3 years ago

7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t

Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

$\frac{x^a}{x^b}=x^{a-b}$

$x^0=1$

$(x^a)(x^b)=x^{a+b}$

$x^{-a}=\frac{1}{x^a}$

$\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=$

$\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=$

$\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=$

$(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=$

$(7^{-5-(-5)})(2^{0-3})=$

$(7^0)(2^{-3})=$

$\frac{1}{2^3}=$

$\frac{1}{8}$

7 0

3 years ago

Leon found the sum 5/6and2/3 to be 11/12. How can you tell that his answer is incorrect without calculating

VARVARA [1.3K]

First , in order to find the answer you need to add the add the numerators which are 5 and 2 = 7 and then you need to find a common denominator.

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4 years ago

Read 2 more answers

How does writing a function rule as an equation help you solve problems with more than one situation or parameter?

Paha777 [63]

Because then you can replace the variables with the actual value and see of the equation is true.

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3 years ago