Answer:
d 20.4 years
Step-by-step explanation:
The equation is
A = Pe ^(rt)
We know that r = .034
We want the money to double so A = 2P
Substitute in
2P = P e ^(.034t)
Divide by P
2P/P = P/P e ^(.034t)
2 = e^ (.034t)
Take the natural log on each side
ln (2) = ln(e^ (.034t))
ln (2) = .034t
Divide by .034
ln (2) /.034 = .034t/.034
ln (2)/.034 = t
20.3867 =t
12/6x its 2x your anwser would be 2x its simple
8/6 and then m/16 is the correct answer
X will be used for the value of money she earned that week.
H represents the normal hours she worked.
D represents the number of days.
Y will represent the hours on the holiday.
Since she would be getting time and a half on the holiday, you would need to find how much time and a half pay would be first.
Time and a half = 5.50(1/2) + 5.50 = $8.25/hr for the day or holiday only.
X = 5.50(H)(D) + 8.25(Y)
Plug in your numbers
X = 5.50(7)(5) + 8.25(4)
X = 192.5 + 33
She made $225.5 that week.
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