Answer:
Last year there were 550 bison in the heard and this year it is 10% larger.
10% is also 10/100 or 0.10
To find 10% of the heard last year
550 x.0.10 = 55. To find the number in the heard this year add 550 (last year) + 55 (10% growth) = 605 or,
to find how many there are now last years heard size was 100% of the heard or 1.00. To find any percent more add it to 1.00 and multiply by the starting amount.
550 x 1.10 = 605
For the second example.
If there are 550 bison in the heard this year, and this year was a decrease of 10% from last year we can express last year's number like this.
550 = (x - (x * 0.10)) simplify;
550 = 1x - 0.10x
550 = 0.90x
Divide both sides by 0.90
x = 611.11 but it's hard to have 0.11 of a bison so realistically 611 bison last year. Subtract 10% or 61 and you indeed have 550 this year.
Answer:
{a | always(true)}
Step-by-step explanation:
this means that this will always be true regardless of the value for a
f(8) = 6 (1-8) +11
= 6 (-7) + 11
= -42 +11
= -31
Answer:
F. Six times a number less nine
This is the only one that doesn't make sense
Sorry if im wrong
Answer:
112
Step-by-step explanation:
To find the least common multiple, we break the numbers down into prime factors
7 = 7
14 = 7*2
16 = 2*8 = 2*4*2 = 2*2*2*2
Then we take the largest number of times it appears in all the numbers
2 appears 4 times so we take take four 2's
7 appears 1 so we take one 7
LCM = 2*2*2*2*7
LCM = 112