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chubhunter [2.5K]
3 years ago
10

PLEASEEW HELPPP WILL MARK BRAINLEST !!pntss

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0

Answer:

the correct answer is choice 2

Step-by-step explanation:

reason being that both bc and ac would both be vertical lines so they have the same slope of undefined

Vesnalui [34]3 years ago
6 0

Answer:

3.) A reflection across the y-axis

Hope this helps!

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Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w
aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0
3 years ago
Why should you generally expect some error when estimating a parameter? (for example, a population? mean) by a statistic? (for e
nexus9112 [7]

This is called as sampling error or sampling variability. Sampling error is the variability that happens because the value of a sample statistic varies from sample to sample. Sampling error is acquired when a population is estimated from a subset, or sample.

8 0
3 years ago
Can someone help me please and thank you!!
Ipatiy [6.2K]

Answer:

Perimeter: perimeter = (12 x 2) + (x-2 times 2)

Area: 12 x (x-2)

Step-by-step explanation:

I hope im right im only in grade 6 so wouldnt  trust me with that :/  

6 0
2 years ago
Fill in the blanks below.
Dmitry_Shevchenko [17]

Answer:

a) <em>Slope of the line m = ∞</em>

<em>b) Slope of the line  m =0</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Step(i):-</em></u>

<em>Given points are ( 7,7) and (7,-8)</em>

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{-8-7 }{7-7  } = \frac{-15}{0} = infinite<em />

<em>                   m = ∞</em>

<u><em>Step(ii):-</em></u>

Given points are (-6,7) and (9,7)

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{7-7  }{9-(-6)  } = \frac{0}{15} = 0<em />

<em>Slope of the line  m =0</em>

6 0
3 years ago
Write an equation of the circle with center , −45 and radius 6 .
IceJOKER [234]
The general equation for a circle, x^2+y^2=1, falls out of the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle is always equal to the sum of the squares of its legs (you might have seen this fact written like a^2+b^2=c^2, where <em>a </em>and <em>b</em> are the legs of a right triangle and <em>c </em>is its hypotenuse. When we fix <em /><em>c</em> in place and let <em>a </em>and <em>b </em>vary (in a sense, at least; their values are still dependent on <em>c</em>), the shape swept out by all of those possible triangles is a circle - a shape defined by having all of its points equidistant from some center.

How do we modify this equation to shift the circle and change its radius, then? Well, if we want to change the radius, we simply have to change the hypotenuse of the triangle that's sweeping out the circle in the first place. The default for a circle is 1, but we're looking for a radius of 6, so our equation, in line with Pythagorus's, would look like x^2+y^2=6^2, or x^{2} +y^2=36.

Shifting the center of the circle is a bit of a longer story, but - at first counterintuitively - you can move a circle's center to the point (a,b) by altering the x and y portions of the equation to read:

(x-a)^2+(y-b)^2
7 0
3 years ago
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