Algebraic fractions are the same as normal fractions, but they have algebraic expressions as the numerator/denominator.
For example,

is a normal fraction, but

is an algebraic fraction.
Answer:
A = 78.5 in ^2
Step-by-step explanation:
Area of a circle = pi * r^2
The radius is d/2
r= 10/2
r =5
A = pi * r^2
Substitute r=5
A = pi *(5)^2
A = 25 pi
We know that pi is approximated by 3.14
A = 25 (3.14)
A = 78.5 in ^2
Answer:

Step-by-step explanation:
<u>Solving Equations Using Successive Approximations</u>
We need to find the solution to the equation

where


The approximation has been already started and reached a state for x=2.5 where


The difference between the results is 0.25, we need further steps to reach a good solution (to the nearest tenth)
Let's test for x=2.4


The new difference is -0.2+0.24=0.04
It's accurate enough, thus the solution is

The answer to your question is 4:10